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SVEN [57.7K]
2 years ago
11

Which one of the following statements is true concerning an object executing simple harmonic motion?

Physics
1 answer:
timurjin [86]2 years ago
4 0

Answer:

D) The objects velocity is zero when its acceleration is a maximum

Explanation:

In a simple harmonic motion, the total energy is constant (if we neglect air resistance and friction), and it is equal to the sum of the elastic potential energy U and the kinetic energy K:

E=K+U=\frac{1}{2}mv^2+\frac{1}{2}kx^2 (1)

where

m is the mass

v is the velocity

k is the spring constant

x is the displacement

As a consequence, since E must remain constant, when K increases U decreases, and vice-versa.

Also, in a simple harmonic motion the acceleration of the system is proportional to the negative of the displacement:

a\propto - x (2)

So, combining (1) with (2), we have the following situations:

- When the displacement is zero (x=0), the acceleration is also zero (a=0), and so the velocity is maximum, because the kinetic energy is maximum

- When the displacement is maximum (x=max), the acceleration is also maximum, while the velocity is zero because the kinetic energy is zero

So, the correct statement is

D) The objects velocity is zero when its acceleration is a maximum

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The gravitational force produce between any two object kept 2.5×10 to the power 4 km apart is 580N.At what distance should they
timofeeve [1]

Answer:

d = 3.54 x 10⁴ Km

Explanation:

Given,

The distance between the two objects, r = 2.5 x 10⁴  Km

The gravitational force between them, F = 580 N

The gravitational force between the two objects is given by the formula

                                         F = GMm/r² newton

When the gravitational force becomes half, then the distance between them becomes

Let us multiply the above equation by 1/2 on both sides

                                        ( 1/2) F = (1/2) GMm/r²

                                                   =  GMm/2r²

                                                   =  GMm/(√2r)²

Therefore, the distance becomes √2d, when the gravitational force between them becomes half

                                           d = √2r = √2 x 2.5 x 10⁴  Km

                                               = 3.54 x 10⁴  Km

Hence, the two objects should be kept at a distance, d = 3.54 x 10⁴  Km so that the gravitational force becomes half.

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1. A car is 140 kg, and drove East 13.5 m/s. Car B is 157 kg and drove West at 10.9 m/s.
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The velocity would switch on the cars
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Write a hypothesis about how the height of the cylinder affects the temperature of the water. Use the "if . . . then . . . becau
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Suppose you first walk 12.0 m in a direction 20 owest of north and then 20.0 m in a direction 40.0osouth of west. How far are yo
alexgriva [62]

Answer:

R=19.5m

\theta = 4.65° S of W

Explanation:

Refer the attached fig.

displacement  of the x and y components

x-component displacement is (R_{x}) = A_{x}+B_{x}

= A \sin(20°) + B \cos(40°)

= -12.0\sin(20°) + 20.0\cos(40°)

= -19.425m

x-component displacement is (R_{y}) = A_{y}+ B_{y}

=  A \cos(20°) - B \sin(40°)

= 12.0\cos(20°) - 20.0\sin(40°)

= -1.579

resultant displacement

∴

R = \sqrt{R_{x}^{2} +R_{y}^{2} }  }

=\sqrt{(-19.425)^{2}+(-1.579)^{2}  }

=19.5m

\theta = \tan^{-1}\left | \frac{R_{x}}{R_{y}} \right |

\theta = \tan^{-1}\left | \frac{1.579}{19.425} \right |

\theta = 4.65° S of W

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2 years ago
What is the x component of (+3m)ι^ And (+3m/s) i^?
expeople1 [14]
The "i" component of a vector is in the x-direction. Therefore, the x-component is 3 m/s.
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2 years ago
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