You are a scientist conducting an experiment on energy transfers. During the reaction you measure a large transfer of heat energ
2 answers:
Answer:
Option A is true
Explanation:
When you are a scientist conducting an experiment on energy transfer .
The reaction in which you measure a large amount of heat energy transfer.
We have to find the units which you should record them in
Energy: It is defined as the capability of doing the work .
When current I is flowing in ampere A V is potential in volt v applied in the experiment and R be resistance in ohm used in experiment for time t in seconds
Then, heat energy ==A-volt=Joule
Heat energy=
Heat energy==Joule
The S.I unit of heat energy is Joules.
Hence, option A is true.
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Answer:
(3) the partial pressure of carbon dioxide above the solution is reduced.
Explanation:
We know , Soda water contains pressured carbon dioxide pressured with cap because we know according to Henry's law partial pressure of the gas is directly proportional to pressure applied. Therefore, is pressurized in the bottle.
But as we open the bottle the pressure decreases the excess (and air) escapes producing effervescence and partial pressure of
decreases. ( Because of Henry's Law)
Hence, it is the required solution.
<u>Answer:</u> The equilibrium concentration of NO after it is re-established is 0.55 M
<u>Explanation:</u>
For the given chemical equation:
The expression of for above equation follows:
.....(1)
We are given:
Putting values in expression 1, we get:
Now, the concentration of NO is added and is made to 0.700 M
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle. This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
The equilibrium will shift in backward direction.
<u>Initial:</u> 0.200 0.200 0.700
<u>At eqllm:</u> 0.200+x 0.200+x 0.700-2x
Putting values in expression 1, we get:
So, equilibrium concentration of NO after it is re-established = (0.700 - 2x) = [0.700 - 2(0.075)] = 0.55 M
Hence, the equilibrium concentration of NO after it is re-established is 0.55 M