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2 years ago

4

A solid cylinder with an unknown radius starts from rest at the top of a 12.0m long ramp inclined 20.3∘ above the horizontal. Ca

lculate the cylinder's final velocity when it reaches the bottom of the ramp.

1 answer:

Vikki [24]2 years ago

8 0

Answer:

2b2t

Explanation:

2b2t

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D or A i'm not that sure

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2 years ago

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A lab technician uses laser light with a wavelength of 670 nm to test a diffraction grating. When the grating is 40.0 cm from th

Juliette [100K]

Answer:

N = 221.4 lines / mm

Explanation:

Given:

- The wavelength of the source λ = 670 nm

- Distance of the grating from screen B = 40.0 cm

- The distance of first bright fringe from central order P = 6.0 cm

Find:

How many lines per millimeter does this grating have?

Solution:

- The derived results from Young's experiment that relates the order of bright fringes about the central order is given by:

sin (Q) = n*λ*N

Where,

n is the order number 0, 1 , 2, 3 , ....

λ is the wavelength of the light source

Q is the angle of sweep respective fringe from central order

N is the number of lines/mm the grating has

- We will first compute the length along which the light travels for the first bright fringe:

L^2 = P^2 + B^2

L^2 = 40^2 + 6^2

L^2 = 1636

L = 40.45 cm

- Now calculate the sin(Q) that the fringe makes with the central order:

sin (Q) = P / L

sin (Q) = 6 / 40.45

- Now we will use the derived results:

N = sin(Q) / n*λ

Where, n = 1 - First order

Plug values in N = (6 / 40.45) / (670 *10^-6)

N = 221.4 lines / mm

8 0

2 years ago

You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase the t

lina2011 [118]

Answer:

W = 172.5 J

Explanation:

given,

mass of the fruit crate = 14.5 kg

initial velocity to lift = 0.500 m/s

increase in the tension = 150 N

lift of crate = 1.15 m

work done by the tension = ?

work done = force x displacement

W = F s cos θ

θ = 0°

W = F s x cos 0

W = 150 x 1.15 x 1

W = 172.5 J

Work done on the crate by the tension force = W = 172.5 J

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2 years ago

A physics student stands on the rim of the canyon and drops a rock. The student measures the time for it to reach the bottom to

madam [21]

Answer:

Canyon is 50.176 meter deep.

Explanation:

The students is standing on the rim of the canyon and drops down a rock from the rim(cliff). We have to find what is the depth of the canyon i.e. how much below is the ground from the cliff.

Given data:

Time = t = 3.2 s

Initial velocity = $v_{i}$ = 0 m/s

Gravitational acceleration = g = 9.8 m/s²

Height = h = ?

According to second equation of motion

$h = v_{i}t + \frac{1}{2}gt^{2}$

As initial velocity is zero, So the first term of right hand side of above equation equal to zero

$h = \frac{1}{2}gt^{2}$

h = (0.5)(9.8)(3.2)²

h = 50.176 m

This means, the rock traveled 50.176 meters to reach the bottom of the Canyon. So, the Canyon is 50.176 meter deep.

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2 years ago

After an arrow is shot, is the force unbalanced or balanced? BRAINLY.

Reil [10]

Answer:

The force is unbalanced

Explanation:

After an arrow is shot, the force acting on the arrow is unbalanced. The resulting net force gives the arrow an initial acceleration which wanes with time and the body is brought to rest.

The net force acting on an arrow is not zero and this indicates that the forces acting on the arrow is unbalanced.

If the force is balanced, the arrow is expect to continue in uniform motion but that is not the case as air resistance has massive impact on this body.

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2 years ago