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UkoKoshka [18]
2 years ago
4

Carry out the following operations as if they were calculations of experimental results, and express each answer in the correct

units with the correct number of significant figures: (a) 5.6792 m + 0.6 m + 4.33 m (b) 3.70 g - 2.9133 g (c) 4.51 cm x 3.6666 cm
Chemistry
1 answer:
FromTheMoon [43]2 years ago
6 0

Explanation:

1. 5.6792 m + 0.6 m + 4.33 m

Adding gives: 10.6092 m

Of the three measurements given, the one with the least number of decimal places has to be considered since we are adding the measurements. 0.6 m has only one decimal place. So the answer has to be rounded off to one decimal place.

Hence the answer = 10.6 m

2. 3.70 g - 2.9133 g

Subtracting gives: 0.7867

The answer has to be rounded off to the least number of decimal places which is 2 , (3.70)

Hence the answer = 0.79 g

3. 4.51 cm * 3.6666 cm

Multiplying gives: 16.536366

For multiplication, the answer needs to be rounded off to the least number of significant figures in the given measurements. 4.51 cm has three significant figures.

So rounding off, the answer = 16.5 cm²

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Calculate the mass of 25,000 molecules of nitrogen gas. (1 mole = 6.02 x 1023 molecules)
Ainat [17]

Hey there!

Molar mass N2 = 28.01 g/mol

Therefore:

28.01 g N2 -------------- 6.02*10²² molecules N2

( mass N2 ?? ) ----------- 25,000 molecules N2

mass N2 =  ( 25,000 * 28.01 ) /  ( 6.02*10²³ )

mass N2 = 700250 / 6.02*10²³

mass N2 = 1.163*10⁻¹⁸ g


Hope that helps!

7 0
2 years ago
Read 2 more answers
A diamond can make permanent marks on glass. It can also cut glass. Most other materſals cannot do this.Which property of a diam
Kaylis [27]
Probably a. hardness
7 0
2 years ago
Balance the following oxidation-reduction reaction: Fe(s)+Na+(aq)→Fe2+(aq)+Na(s) Express the coefficients as integers separated
aliina [53]

Answer:

The answer to your question is: 1, 2, 1, 2

Explanation:

                       1 Fe(s)  + 2 Na⁺(aq)  → 1 Fe²⁺(aq)  + 2 Na(s)

                             Fe⁰   -   2e⁻       ⇒           Fe⁺²        Oxidases

                             Na⁺   +  1 e⁻       ⇒           Na⁰         Reduces

                      1 x ( 1 Fe⁰      ⇒         1 Fe⁺²)      Interchange number of

                      2 x ( 2Na⁺       ⇒       2 Na⁰ )      electrons

6 0
2 years ago
Complete ionic equation K2CO3(aq)+2CuF(aq) → Cu2CO3(s)+2KF(aq) Examine each of the chemical species involved to determine the io
Fudgin [204]

Answer:

2K+(aq) + CO3²¯(aq) + Ca^2+(aq) + 2F¯(aq) —› Cu2CO3(s) + 2K+(aq) + 2F¯(aq)

Explanation:

K2CO3(aq) + 2CuF(aq) → Cu2CO3(s) + 2KF(aq)

The complete ionic equation for the above equation can be written as follow:

In solution, K2CO3 and CuF will dissociate as follow:

K2CO3(aq) —› 2K+(aq) + CO3²¯(aq)

CuF(aq) —› Ca^2+(aq) + 2F¯(aq)

Thus, we can write the complete ionic equation for the reaction as shown below:

K2CO3(aq) + 2CuF(aq) —›

2K+(aq) + CO3²¯(aq) + Ca^2+(aq) + 2F¯(aq) —› Cu2CO3(s) + 2K+(aq) + 2F¯(aq)

8 0
2 years ago
A sample of ammonia gas at 75°c and 445 mm hg has a volume of 16.0 l. what volume will it occupy if the pressure rises to 1225 m
ioda
In this kind of exercises, you should  use the "ideal gas" rules: PV = nRT
P should be in Pascal: 
445mmHg = 59328Pa
1225mmHg = 163319Pa

V should be in cubic meter:
16L = 0.016 m3

R = \frac{PV}{nT} = constant
\frac{P1 V1}{n T} = \frac{P2 V2}{n T}
==> P1 * V1 = P2 * V2
V2 = \frac{P1 V1}{P2} = \frac{445 0.016}{1225}
V2 = 0.00581 m3 = 5.81 L


7 0
2 years ago
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