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Free_Kalibri [48]
2 years ago
8

A rectangular wooden block measures 10.0 cm × 4.00 cm × 2.00 cm. When the block is placed in water, it floats horizontally, with

its bottom face 1.65 cm below the surface. What is the density of the wood?
Physics
1 answer:
Alex Ar [27]2 years ago
5 0

Answer:

825 kgm⁻³

Explanation:

ρ = density of wood = ?

ρ' = density of water = 1000 kgm⁻³

V = volume of wood = 10 x 4 x 2 = 80 cm³ = 80 x 10⁻⁶ m³

V' = Volume of water displaced = 10 x 4 x 1.65 = 66 cm³ = 66 x 10⁻⁶ m³

Using equilibrium of force in vertical direction

Force of buoyancy = Weight of the wood

ρ' V' g = ρ V g

ρ' V' = ρ V  

(1000) (66 x 10⁻⁶) = ρ (80 x 10⁻⁶)

ρ = 825 kgm⁻³

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Tech A says that tires are marked with a date code listing the date the tires should be discarded. Tech B says that any tires wi
9966 [12]

Tech B is saying correct.

<u>Explanation:</u>

Yes, tires are provided with date codes but those date codes are correlated with manufacturing or production dates and not with the date of discarding. But it is difficult to understand or decode the date code. The tires with 3 digit code represent very old tires while the tires with 4 digit code are made after 1999.

In the four-digit date code, the first two digits indicate the week during which that tire was produced and the last two digits indicate the year of production. So the statement said by Tech A is wrong and the statement said by Tech B is correct.

4 0
2 years ago
Which of the following equations illustrates the law of conservation of matter?
AlladinOne [14]

Answer: The correct answer is option (B).

Explanation:

Law of conservation of mass: 'In a chemical reaction, mass neither be created nor be destroyed'

In the balance chemical equation,total mass of the reactants is equal to the total mass of the products.

A. 2Na+Cl_2\rightarrow  NaCl

[2\times (23 g/mol)+(35.5 g/mol)\times 2]=[23 g/mol+35.5 g/mol]

117 g/mol  ≠ 58.5 g/mol

Law of Conservation of Mass not followed.

B.2Na+Cl_2\rightarrow 2NaCl

[2\times (23 g/mol)+(35.5 g/mol)\times 2]=2\times [23 g/mol+35.5 g/mol]

117 g/mol  =  117 g/mol

Law of Conservation of Mass is followed.

C.2Na+2Cl_2\rightarrow 2NaCl

[2\times (23 g/mol)+(35.5 g/mol)\times 2]=2\times [23 g/mol+35.5 g/mol]

188 g/mol  ≠ 117 g/mol

Law of Conservation of Mass not followed.

D.Na+Cl_2\rightarrow 2NaCl

[(23 g/mol)+(35.5 g/mol)\times 2]=2\times [23 g/mol+35.5 g/mol]

94 g/mol  ≠ 117 g/mol

Law of Conservation of Mass not followed.

Hence, the correct answer is option (B).

5 0
2 years ago
50 POINTS! A Boy throws a ball horizontally a distance of 22m downrange from the top of a tower that is 20.0m tall. What is his
DerKrebs [107]

The ball's horizontal and vertical velocities at time t are

v_x=v_{xi}

v_y=v_{yi}-gt

but the ball is thrown horizontally, so v_{yi}=0. Its horizontal and vertical positions at time t are

x=v_{xi}t

y=20.0\,\mathrm m-\dfrac g2t^2

The ball travels 22 m horizontally from where it was thrown, so

22\,\mathrm m=v_{xi}t

from which we find the time it takes for the ball to land on the ground is

t=\dfrac{22\,\rm m}{v_{xi}}

When it lands, y=0 and

0=20.0\,\mathrm m-\dfrac{9.8\frac{\rm m}{\mathrm s^2}}2\left(\dfrac{22\,\rm m}{v_{xi}}\right)^2

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7 0
2 years ago
If a freely suspended vertical spring is pulled in downward direction and then released, which type of wave is produced in the s
larisa [96]

Answer:

longitudinal wave

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3 0
2 years ago
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In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal
SpyIntel [72]

Answer:

A) F_g = 26284.48 N

B) v = 7404.18 m/s

C) E = 19.19 × 10^(10) J

Explanation:

We are given;

Mass of satellite; m = 3500 kg

Mass of the earth; M = 6 x 10²⁴ Kg

Earth circular orbit radius; R = 7.3 x 10⁶ m

A) Formula for the gravitational force is;

F_g = GmM/r²

Where G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²

Plugging in the relevant values, we have;

F_g = (6.67 × 10^(-11) × 3500 × 6 x 10²⁴)/(7.3 x 10⁶)²

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B) From the momentum principle, we have that the gravitational force is equal to the centripetal force.

Thus;

GmM/r² = mv²/r

Making v th subject, we have;

v = √(GM/r)

Plugging in the relevant values;

v = √(6.67 × 10^(-11) × 6 x 10²⁴)/(7.3 x 10⁶))

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C) From the energy principle, the minimum amount of work is given by;

E = (GmM/r) - ½mv²

Plugging in the relevant values;

E = [(6.67 × 10^(-11) × 3500 × 6 × 10²⁴)/(7.3 x 10⁶)] - (½ × 3500 × 7404.18)

E = 19.19 × 10^(10) J

5 0
2 years ago
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