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Inessa [10]
2 years ago
7

A car starts out when the air temperature is 288 K. The air pressure in the tires is 460 kPa. After driving a while, the tempera

ture of the air in the tires increases to 298 K. What is the pressure in the tires at that point, assuming the volume remains constant?
(A) 476 kPa
(B) 498 kPa
(C) 488 kPa
(D) 563 kPa
(E) 512 kPa
Physics
2 answers:
VARVARA [1.3K]2 years ago
8 0

Answer:

<em>A. The final pressure at the tire would be 476 kPa</em>

Explanation:

Since the volume is constant the ideal gas equation would be used to obtain the final pressure at the tire.

Given

the initial temperature T_{1} = 288 K

the initial pressure P_{1} = 460 k Pa

the final temperature T_{2} = 298 K

the final pressure P_{2} = ?

Using the ideal gas equation;

PV = nRT

P_{1} / T_{1}  = P_{2} / T_{2}

Making P_{2} the subject formula

P_{2}  = (P_{1} x T_{2} ) / T_{1}

P_{2}  = (460 x 298) / 288

P_{2}  = 475.972 kPa

P_{2}  ≈ 476 kPa

Therefore the final pressure at the tire would be 476 kPa

Burka [1]2 years ago
4 0

Answer:

(A) 476 kPa

Explanation:

If the volume remains constant, the ideal gas law says:

P/T=constant

so: P1/T1=P2/T2

P2=P1*T2/T1=460*298/288=476KPa

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