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matrenka [14]
2 years ago
7

Two identical grasshoppers jump into the air with the same initial speed and experience no air resistance. Grasshopper A goes st

raight up, but grasshopper B goes up at a 66° angle above the horizontal. Which of the following statements about these grasshoppers are correct? (There could be more than one correct choice.
Choices below:

a.) At their highest point, both of them have the same amount of mechanical energy.
b.) At their highest point, grasshopper B is moving faster than grasshopper A.
c.) At their highest point, both of them have the same amount of kinetic energy.
d.) At their highest point, both of them have the same amount of gravitational potential energy.
e.)At their highest point, grasshopper A has more gravitational potential energy than grasshopper B.
Physics
1 answer:
avanturin [10]2 years ago
7 0

Answer:

a.) At their highest point, both of them have the same amount of mechanical energy.

Explanation:

Grasshopper A jumps upwards with speed v while grasshopper B jumps at an angle of 66 degree with horizontal at same speed

so vertical speed of B is given

v_y = v sin66 = 0.91v

v_x = v cos66 = 0.41v

So when both the grasshopper will jump upwards they both will attain different maximum heights

Since initial speed of both grasshopper is same so their mechanical energy is always conserved

So mechanical energy of grasshopper A is given as

U = \frac{1}{2}mv^2

Mechanical energy of grasshopper B is given as

U = \frac{1}{2}m(vcos^2\theta) + \frac{1}{2}m(vsin\theta)^2

U = \frac{1}{2}mv^2

So we have

a.) At their highest point, both of them have the same amount of mechanical energy.

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If the envelope and gondola have a total mass of 4300 kg, what is the maximum cargo load when the blimp flies at a sea-level loc
geniusboy [140]

Complete question:

The classic Goodyear blimp is essentially a helium balloon— a big one, containing 5700 m³ of helium. If the envelope and gondola have a total mass of 4300 kg, what is the maximum cargo load when the blimp flies at a sea-level location? Assume an air temperature of 20°C.

Answer:

52.4 kN

Explanation:

The helium at 20°C has a density of 0.183 kg/m³, and the cargo load is the weight of the system, which consists of the envelope, the gondola, and the helium.

The helium mass is the volume multiplied by the density, thus:

mHe = 5700 * 0.183 = 1043.1 kg

The total mass is then 5343.1 kg. The weight is the mass multiplied by the gravity acceleration (9.8 m/s²), so:

W = 5343.1*9.8

W = 53362.38 N

W = 52.4 kN

5 0
2 years ago
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A man exerts a force on a large couch by pushing on it. Which of the following must be a true statement about the couch after he
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Answer: the answer is c

Explanation:

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2 years ago
In the late 19th century, great interest was directed toward the study of electrical discharges in gases and the nature of so-ca
gizmo_the_mogwai [7]

Answer:

A) He finds the same value of q / m for different materials , B)      y = ½ (q / m) E L² / v₀ₓ² , C) v = E / B , D)   B = 2.13 10⁻⁶ T, E) For the first part I have two off-center points., For the second part I can center one point but the other is off center

Therefore the third statement is correct

Explanation:

Part A

Thomson's experiments are the first proof that the atoms that until now were considered indivisible were constituted by different elements, in these experiments Thomson himself the ratio q / m of several cathodes and always found the same value, which allowed to establish that In atoms there are two types of particles, some of which are mobile and others are still.

When examining his statements the correct one is: He finds the same value of q / m for different materials

Part B

For this part let's use Newton's second law

        F = ma

        q E = m a

        a = q / m E

We use the kinematic relationship

          y = voy t - ½ to t²

          x = v₀ₓ t

The initial vertical velocity of electrons is zero

           y = ½ a (x / v₀ₓ)²

We replace

           y = ½ (q / m) E L² / v₀ₓ²

Part C

If there is no deflection, the electric and magnetic forces are the same and in the opposite direction

         Fm = Fe

         q v B = q E

          v = E / B

Part D

       

        We replace

        y = ½ (q / m) E L² / (E / B)²

         y = ½ (q / m) L² B² / E

If we do not want any deflection the magnetic field has to return the electrons the amount that they lower y = -4.12 cm

      -4.12 10⁻² = ½ q / m 0.12² B² / 1.1 10³

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      q / m = -1.758 10¹¹ C/ kg

      B = √ 0.259 1.758 10¹¹ = √ 4.55 10⁻¹²

      B = 2.13 10⁻⁶ T

Part E

As the charge that the two particles is different

For the first part I have two off-center points.

For the second part I can center one point but the other is off center

Therefore the third statement is correct

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Answer:

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See attached file

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Answer:

Option(a) is the correct answer to the given question .

Explanation:

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