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Goryan [66]
2 years ago
12

The gas tank of a car is filled with a nozzle that discharges gasoline at a constant flow rate. Based on unit considerations of

quantities, choose the correct relation for the filling time in terms of the volume V of the tank (in L) and the discharge rate
Physics
1 answer:
mojhsa [17]2 years ago
4 0

Answer:

V=\dfrac{dV}{dt}.t

Explanation:

Given that nozzle discharge at constant flow rate.

Volume of tank is V

Lets  constant flow rate =Q

We know that

Q=\dfrac{dV}{dt}\ L^3/s

To find the time t,at a volume V

V = Q .t

V=\dfrac{dV}{dt}.t

Where t is the filling time of volume .

dV/dt is the volume floe rate .

Q is the discharge.

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If a 110 kg go-cart traveling at a velocity of 13.41 m/s has a collision with an impulse of 615 Nxs, what is the
mafiozo [28]

Answer:

5.59 m/s

Explanation:

We are given;

Mass = 110 kg

Initial velocity: u = 13.41 m/s

Force = 615 N

Time(t) = 1 s

Now, the formula for force is;

Force = mass x acceleration

Thus;

615 = 110 × acceleration

\Acceleration(a) = 615/110 = 5.591 m/s²

Now, using Newton's first law of motion, we can find acceleration (a). Thus;

v = u + at

v = 13.41 + (5.591 × 1)

v ≈ 19 m/s

So,the change in velocity is;

Final velocity(v) - Initial velocity(u) = 19 - 13.41 = 5.59 m/s

6 0
2 years ago
1. A 930-kg car traveling 56 km/h comes to a complete stop in 2.0 s. What is the
Juli2301 [7.4K]

The force exerted on the car during this stop is 6975N

<u>Explanation:</u>

Given-

Mass, m = 930kg

Speed, s = 56km/hr = 56 X 5/18 m/s = 15m/s

Time, t = 2s

Force, F = ?

F = m X a

F = m X s/t

F = 930 X 15/2

F = 6975N

Therefore, the force exerted on the car during this stop is 6975N

6 0
2 years ago
A 4.0-m-diameter playground merry-go-round, with a moment of inertia of 350 kg⋅m2 is freely rotating with an angular velocity of
Flauer [41]

Answer:

v = 4.375\,\frac{m}{s}

Explanation:

The situation of the system Ryan - merry-go-round is modelled after the Principle of the Angular Momentum Conservation:

(350\,kg\cdot m^{2})\cdot (1.5\,\frac{rad}{s} ) - (2\,m)\cdot (60\,kg)\cdot v = 0\,kg\cdot \frac{m^{2}}{s}

The initial speed of Ryan is:

v = 4.375\,\frac{m}{s}

5 0
2 years ago
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A car travels three-quarters of the way around a circle of radius 20.0 m in a time of 3.0 s at a constant speed. the initial vel
schepotkina [342]
20.3 divided by 3.0 will get u velocity and v times 3.0s 
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2 years ago
A 12.0-kg shell is launched at an angle of 55.0 ∘ above the horizontal with an initial speed of 150 m/s. when it is at its highe
Stolb23 [73]
Hey there! Congratulations on posting your first question! I just want to thank you for taking the initiative to check out Brainly. With Brainly, students combine their strengths and talents to tackle problems together and by answering questions, you’ve helped several students learn even more, both quickly and effectively. If you ever have any questions or concerns feel free to PM me or check out our help center (faq.brainly.com). Thanks! 
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