Question

Consider the nucleophilic addition reaction of 2‑butanone with excess propyl magnesiumbromide, made in situ by reacting 1‑bromopropane with metallic magnesium, to make 3‑methyl‑3‑hexanol. 2-butanone 1-bromopropane magnesium 3-methyl-3-hexanol ????d =0.81 g/mL ????d =1.35 g/mL ????d =0.82 g/mL A reaction was performed in which 0.40 mL0.40 mL of 2‑butanone was reacted with an excess of propyl magnesiumbromide to make 0.38 g0.38 g of 3‑methyl‑3‑hexanol. Calculate the theoretical yield and percent yield for this reaction.

Answer 1

Answer:

Theoretical yield is 0,52 g and percent yield for this reaction is 73%

Explanation:

The theoretical yield is the maximum amount of product a chemical reaction could create based on chemical equations. The percent yield is the ratio between theoretical yield and obtained yield times 100.

In the reaction:

2-butanone + propyl magnesium bromide → 3-methyl-3-hexanol

The theoretical yield with 0,40 mL is:

0,40 mL×$\frac{0,81g}{1mL}$×$\frac{1mol2-butanone}{72,11g}$×$\frac{1mol 3-methyl...}{1mol2-butanone}$×$\frac{116,2g}{1mol3-methyl...}$ = 0,52 g

Thus, percent yield for this reaction is:

0,38g/0,52g×100 = 73%

I hope it helps!