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2 years ago

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You then measure Polly's internal temperature to be 13oC, which is quite a drop from the normal human body temperature of 37oC.

And weighing Polly, you find her mass to be 60 kg. Now, subtracting the heat warming the water from the surrounding environment, we assume Polly gave up only 5000 kJ of thermal energy to warm the bath. With these numbers, determine Polly's specific heat in units J/(kgoC).

1 answer:

ankoles [38]2 years ago

5 0

Answer:

The specific heat is 3.47222 J/kg°C.

Explanation:

Given that,

Temperature = 13°C

Temperature = 37°C

Mass = 60 Kg

Energy = 5000 J

We need to calculate the specific heat

Using formula of energy

$Q= mc\Delta T$

$c =\dfrac{Q}{m\Delta T}$

Put the value into the formula

$c=\dfrac{5000}{60\times(37-13)}$

$c=3.47222\ J/kg^{\circ}C$

Hence, The specific heat is 3.47222 J/kg°C.

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Explanation:

The sportsman that lifts the stone with a greater mass needs a higher force (El deportista que levanta la piedra con mayor masa necesita una mayor fuerza):

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2 years ago

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Answer:

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1 joule [J] = 6241506363094 mega-electrón voltio [MeV]

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