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Archy [21]
2 years ago
5

Disprove the following statement by giving a counterexample. (Enter your answers as a comma-separated list.) For every integer p

, if p is prime then p2 − 1 is even.
Mathematics
1 answer:
ANTONII [103]2 years ago
7 0

Answer:

The given statement is not always true.

Step-by-step explanation:

The given statement is not true,

We have the statement that,

p² - 1 is even number; if p is any prime number.

But this statement is not true always as,

Examples: 2 is a prime number and 2² - 1 = 3

But, 3 is not even.

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A recipe states that 5 servings of peanuts have 1,250calories. How many calories is 2 servings of peanuts? *
MrMuchimi

Answer:

500 calories

Step-by-step explanation:

divide the 1250 calories by the initial five servings and you get 250 then multiply that by the 2 servings they are asking for and you get 500 calories

4 0
2 years ago
Read 2 more answers
What is Question I (if m<EBF = 117°, fine m<ABE)​
Natasha_Volkova [10]

Answer:

m∠ABE = 27°

Step-by-step explanation:

* Lets look to the figure to solve the problem

- AC is a line

- Ray BF intersects the line AC at B

- Ray BF ⊥ line AC

∴ ∠ABF and ∠CBF are right angles

∴ m∠ABF = m∠CBF = 90°

- Rays BE and BD intersect the line AC at B

∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure

∴ BE is the bisector of angle ABD

∵ m∠EBF = 117°

∵ m∠EBF = m∠ABE + m∠ABF

∵ m∠ABF = 90°

∴ 117° = m∠ABE + 90°

- Subtract 90 from both sides

∴ m∠ABE = 27°

4 0
2 years ago
Read 2 more answers
At the bank, Brent exchanges $50 in bills for 50 one-dollar coins. The total mass of the coins is 405 grams. ESTIMATE the mass o
Anarel [89]
To find the answer, you should divide 405 by 50 to find the mass of one coin. The formula should look like this:
\frac{405}{50}
= 8.1
The exact mass is 8.1 grams, but because you want an estimate, the answer should be
About 8 grams for the mass of 1 one-dollar coin
4 0
2 years ago
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Write the expanded form of 4(1/4a+b-6)
vodomira [7]

Answer: a + 4b -24

Step-by-step explanation:

4 x 1/4a = 1a

4 x b = 4b

4 x -6 = -24

4 0
2 years ago
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The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the foll
Mrrafil [7]

Answer

given,

thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

X = U[0.95,1.05]           0.95≤ x ≤ 1.05

the cumulative distribution function of flange

F(x) = P{X≤ x}=\dfrac{x-0.95}{1.05-0.95}

                     =\dfrac{x-0.95}{0.1}

b) P(X>1.02)= 1 - P(X≤1.02)

                   = 1- \dfrac{1.02-0.95}{0.1}

                   = 0.3

c) The thickness greater than 0.96 exceeded by 90% of the flanges.

d) mean = \dfrac{0.95+1.05}{2}

              = 1

   variance = \dfrac{(1.05-0.95)^2}{12}

                  = 0.000833

4 0
2 years ago
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