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aivan3 [116]
2 years ago
4

Combustion reactions are relatively easy to carry out and study, and their data can be combined to give enthalpies of other type

s of reactions. As an illustration, calculate the standard enthalpy of hydrogenation of cyclohexane given that the standard enthalpies of combustion of the two compounds are -3752 kJ mol-1 (cyclohexene) and -3953 kJ mol-1 (cyclohexane).
Chemistry
1 answer:
sammy [17]2 years ago
7 0

Answer:

ΔH = -201 kJ/mol

Explanation:

The Hess' Law say that the enthalpy of one reaction is equal to the sum of all the steps:

C6H12 + 9O2 --> 6CO2 + 6H2O    ΔH = -3752 kJ

C6H10 + 17/2O2 --> 6CO2 + 5H2O ΔH = -3953 kJ

C6H10 + H2O --> C6H12 + 1/2O2 ΔH = -3953 + 3752

ΔH = -201 kJ/mol

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Select the correct set of quantum numbers (n, l, ml, ms) for the first electron removed in the formation of a cation for stronti
matrenka [14]

Answer:

5,0,0,-1/2

Explanation:

The quantum numbers are a way to characterize the electrons, and so, identify the region that it's more probable to find it (orbital). They are:

- Principal quantum number (n): represents the shell or level, and varies from 1 to 7, and are represented by the letter K, L, M, N, O, P, and Q.

- Azimuthal quantum number (l): represents the subshell or sublevel, and is represented by 0,1,2,3.., and for the letters s, p, d, f,...

- Magnetic quantum number (ml): represents the orbital. It varies from -l to +l passing by 0. Each orbital can have 2 electrons.

- Spin quantum number (ms): represents the spin of the electron. It can be +1/2 or -1/2.

The strontium has an atomic number equal to 38, by the Linus Pauling's diagram, the electronic distribution is:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²

The valence electron is at the subshell 5s, which has only one magnetic quantum number: 0. Because it has 2 electrons, the first one has spin =1/2, and the other -1/2. So the first electron of the formation of cation has quantum numbers:

n = 5; l = 0; ml = 0; ms = -1/2

7 0
2 years ago
25.0 mL of an HBr solution were titrated with 29.15 mL of a 0.205 M LiOH solution to reach the equivalence point. What is the mo
krok68 [10]

HBr reacts with LiOH and forms LiBr and H₂O as the products. The balanced reaction is

LiOH(aq) + HBr(aq) → LiBr(aq) + H₂O(l)

Molarity (M) = moles of solute (mol) / volume of the solution (L)

Molarity of LiOH = 0.205 M

Volume of LiOH = 29.15 mL = 29.15 x 10⁻³ L

Hence,

moles of LiOH = molarity x volume of the solution

= 0.205 M x 29.15 x 10⁻³ L

= 5.97575 x 10⁻³ mol

The stoichiometric ratio between LiOH and HBr is 1 : 1.

Hence,

moles of HBr in 25.0 mL = moles of LiOH added

= 5.97575 x 10⁻³ mol

Hence, molarity of HBr = 5.97575 x 10⁻³ mol / 25.00 x 10⁻³ L

= 0.23903 M

≈ 0.239 M

Hence, the molarity of the HBr is 0.239 M.

6 0
2 years ago
Read 2 more answers
A young deer needs cell division to grow to its full size. However, a deer's cells continue to divide through its whole life. Wh
Mumz [18]

Answer:

D :)

Explanation:

Cells die and the new cells that are being produced are replaced by new living cells. (If cell division prevented cancer, we'd all be saved by now.)

6 0
2 years ago
Why does it conduct more before and after this minimum point?
Leona [35]

Let me give you an example. Lets say that we have an amount of Ba(OH)2 compared to H2SO4. And let's say that the Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4-2. So, what happens here is that w<span>hen the conductivity is at a minimum it means that stoichiometric amounts of Ba(OH)2 and H2SO4 are present and the only materials you can find there in the reaction vessel are H2O and BaSO4. That is why it conduct more before and after this minimum point</span>
3 0
2 years ago
Calculate the grams of sugar present in a 355 mL can of soda if the water in the can weighs 355 g and the density of the soda is
LenKa [72]
Mass of sugar=Mass of solution - mass of water

=1.07X355 - 355
= 24.85g
7 0
2 years ago
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