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2 years ago

Oxidation number of au in kaucl4

Chemistry

2 answers:

scZoUnD [109]2 years ago

8 0

+7 is the correct answer for this.

DanielleElmas [232]2 years ago

3 0

KauCl4 :

K = + 1

au = + 7

Cl = - 2

hope this helps!

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An atom of helium has a radius = and an average speed in the gas phase at of . . Suppose the speed of a helium atom at has been

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Answer:

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Explanation:

Given that

Speed of neon = 350 m/s

Un-certainity in speed= (0.01 ÷ 100) × 350

= 0.035 m/s

As per heisenberg uncertainty principle

$\triangle X\times m \triangle \ v\geq \frac{h}{4\pi }$ ....... (i)

substituting the values in equation (i)

$\triangle X = 4.49 \times 10^-^8 m$

In terms of rNe i.e 38 pm = $38\times 10^-^1^2$

$\triangle X = \frac{4.49\times 10^-^8}{38\times 10^-^1^2}$

$= 0.118 \times 10^4 \times (rNe)$

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2 years ago

The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54.8. A reaction vessel contains 0.0890 M H

Mars2501 [29]

Answer: The reaction is not at equilibrium and will proceed to make more products to reach equilibrium.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

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For the given chemical reaction:

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The expression for $Q$ is written as:

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2 years ago

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Alexus [3.1K]

Answer:

0.3229 M HBr(aq)

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Explanation:

Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown concentration HBr(aq) required 18.45 mL of 0.3500 M NaOH(aq) to neutralize it, to the point where thymol blue indicator changed from pale yellow to very pale blue. Calculate the concentration (molarity) of Stu's HBr(aq) sample.

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2 years ago

At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?

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The temperature that would the volume of a gas be 0.550l if it had a volume of 0.432 L at -20.0 c is calculated using the Charles law formula

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T1= (0.55lL x253)/ 0.432 l = 322.11 K or 322.11-273 = 49.11 C

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2 years ago

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2 years ago

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