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prisoha [69]
2 years ago
3

Consider the balanced equation below. PCI3+CI2>PCI5. what is the mole ratio of PCI3 to PCI5?

Chemistry
1 answer:
AlexFokin [52]2 years ago
4 0
<h3>Answer:</h3>

The mole ratio of PCl₃ to PCl₅ is 1 : 1

<h3>Explanation:</h3>

We are given the balanced equation;

PCI₃ + CI₂ → PCI₅

  • When an equation is balanced one can get the mole ratio of the elements or compounds involved in the reaction.
  • The mole ratio shows the ratio of moles of any two elements or compounds used or produced in a chemical reaction.
  • In this case, the mole ratio of PCl₃ to PCl₅ is 1 : 1.
  • It means that for every 1 mole of PCl₃ that reacts, 1 mole of PCl₅ is produced.
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7. Two teams are competing in a tug-of-war contest. Team A is pulling at 4000N and Team B is pulling at 4900N is the opposite di
Leto [7]
Basically team B would win since it is exerting a force of 900N unlike team A ( you can tell by doing 4900N minus 4000N ). It is very unbalanced.

5 0
2 years ago
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Magnesium reacts with a certain element to form a compound with the general formula MgX. What would the most likely formula be f
Rama09 [41]

Answer:

K2X

Explanation:

Valency can be defined as the combining power of an element. It is the valency that dictates the value an element will have when writing a chemical formula for its compound.

MgX is a compound of magnesium and an element X. The valency of magnesium in most of its compound is +2. Now for the 2 to have been absent in the chemical formula, this shows that the element X itself have a valency if -2 for the valencies of both to have canceled out.

Now considering the element potassium, it is an alkaline metal belonging to group 1 of the periodic table. Hence, it is expected that it has a valency of +1

Forming a compound with element X means there would be an exchange of valencies between the two. We have established that x has a valency of -2. The formula of the compound thus formed by exchanging the valencies of both element would be K2X

4 0
2 years ago
What is the concentration of a solution made with 0.150 moles of KOH in 400.0 mL of solution?
otez555 [7]

Answer:

concentration = \frac{0.15}{0.4}=0.375 mol/L

Explanation:

Concentration: i is defined as the mole per litre.

concentration = \frac{mole}{volume in L}

mole=0.15

volume=400 ml=0.4 litre

concentration = \frac{0.15}{0.4}=0.375 mol/L

6 0
2 years ago
PLEASE HELP!!! The image represents the reaction between a certain number of molecules of N2 and H2.
77julia77 [94]

Answer:

  • <u><em>The leftover reactant is the nitrogen gas, N₂.</em></u>

Explanation:

As per your description:

<u>1. Square on the left: N₂(g)</u>

  • 3 units of two joint circles: this represents 3 molecules of nitrogen gas, N₂(g).

<u>2. Square on the right: H₂(g)</u>

  • 3 units of two joint circles: this represents 3 molecules of hydrogen gas, H₂(g).

<u>3. Reaction</u>

If the maximum possible amount of NH₃ is formed during the reaction, you assume that the reaction goes to completion.

The chemical equation that represents the reaction is:

  • N₂(g) +  H₂(g) → NH₃(g)

Which must be balanced:

  • N₂(g) +  3H₂(g) → 2NH₃(g)

That means that 1 molecule (or 1 mol) of N₂(g) reacts with 3 molecules (or 3 moles ) of  H₂(g) to produce 2 molecules (or 2 moles) of NH₃(g).

Since, the squares show that there are 3 molecules of each reactant, the 3 molecules of hydrogen gas will be able to react with 1 molecule of nitrogen gas. When that happens, all the hydrogen gas is consumend and yet two molecules of nitrogen gas will remain unreacted. Hence, the nitrogen gas is the leftover reactant.

4 0
2 years ago
Read 2 more answers
2. If 2.50g of sodium hydroxide is being reacted with 4.30g of magnesium chloride, how many grams of magnesium hydroxide would b
Virty [35]

Answer:

1.822 g of magnesium hydroxide would be produced.

Explanation:

Balanced reaction: 2NaOH+MgCl_{2}\rightarrow Mg(OH)_{2}+2NaCl

     Compound                                 Molar mass (g/mol)

         NaOH                                           39.997

         MgCl_{2}                                           95.211

        Mg(OH)_{2}                                        58.3197

So, 2.50 g of NaOH = \frac{2.50}{39.997} mol of NaOH = 0.0625 mol of NaOH

      4.30 g of MgCl_{2}  = \frac{4.30}{95.211} mol of MgCl_{2} = 0.0452 mol of MgCl_{2}

According to balanced equation-

2 mol of NaOH produce 1 mol of Mg(OH)_{2}    

So, 0.0625 mol of NaOH produce (\frac{0.0625}{2}) mol of NaOH or 0.03125 mol of NaOH

1 mol of MgCl_{2} produces 1 mol of Mg(OH)_{2}

So, 0.0452 mol of MgCl_{2} produce 0.0452 mol of Mg(OH)_{2}

As least number of moles of Mg(OH)_{2} are produced from NaOH therefore NaOH is the limiting reagent.

So, amount of Mg(OH)_{2} would be produced = 0.03125 mol

                                                                           = (0.03125\times 58.3197) g

                                                                           = 1.822 g

6 0
2 years ago
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