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Lynna [10]
2 years ago
7

A mass of 30.0 grams hangs at rest from the lower end of a long vertical spring. You add different amounts of additional mass ΔM

to the end of the spring and measure the increase in length Δl of the spring due to the additional mass. You plot your data in the form Δl (vertical axis) versus ΔM (horizontal axis). Plotted this way, your data lies very close to a straight line that has slope 0.0520 m/kg. What is the force constant k of the spring? Use g = 9.80 m/s2.
Physics
1 answer:
MaRussiya [10]2 years ago
5 0

Answer:

k=188.46 N/m

Explanation:

Given that

m= 30 gm

Additional mass = ΔM

Lets take spring coefficient = k

at the equilibrium position

F= k  Δl =( m +  ΔM)g

Δl = change in the spring length

k  Δl = ( m +  ΔM)g

Δl = m g /k + g/k ΔM                     ---------------1

We know that equation of line given as

y = c + S x                         -----------------2

By compare equation 2 and 1

slope = s

S= g/k

Given that slope S= 0.052 m/kg

S =g/ k= 0.052

g=9.8 m/s²

9.8 = 0.052 k

k=188.46 N/m

So the spring constant is 188.46 N/m

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 q' = h*(pi*D)*(Ts-Tinf)
 and solving for the heat transfer convection coefficient, find
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3 0
2 years ago
Indigenous people sometimes cook in watertight baskets by placing hot rocks into water to bring it to a boil. What mass of 500ºC
scoray [572]

Answer:

m = 4.65 kg

Explanation:

As we know that the mass of the water that evaporated out is given as

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Q = 56511 J

now the heat required by remaining water to bring it from 15 degree to 100 degree

Q_2 = ms\Delta T

Q_2 = (4 - 0.025)(4186)(100 - 15)

Q_2 = 1.41\times 10^6J

total heat required for above conversion

Q = 56511 + 1.41 \times 10^6 = 1.47 \times 10^6 J

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m(790)(500 - 100) = 1.47 \times 10^6

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4 0
2 years ago
What mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 ∘C? The heat of vaporization of water at
Stolb23 [73]

Answer:

m = 0.111 kg

Explanation:

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Q = m s\Delta T

here we know that

m = 70 kg

s = 3840 J/kg K

\Delta T = 1.00^o C

now we know that

Q = (70 kg)(3840 J/kg ^oC)(1 ^o C)

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7 0
2 years ago
Come si compongono due forze che agiscono in diversi punti di un corpo rigido? Oof
bagirrra123 [75]

Answer:

Explanation:

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7 0
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Answer:

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2. 18m

Explanation:

See attached file

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2 years ago
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