Question

A baseball of mass m = 0.16 kg is suspended vertically from a tree by a string of length L = 1.4 m and negligible mass. Take z as the upward vertical direction. A short-duration force F = Fyj + Fzk is applied to the baseball by a bat, momentarily creating a torque τ about the top of the string.Enter an expression for the torque due to the given force about the top of the string, in terms of m, L, Fy F , and the unit vectors i

Answer 1

Answer:

$\tau = L F_y \hat i$

Explanation:

As we know that torque due to applied force is given as

$\tau = \vec r \times \vec F$

here we know that

$\vec r = -L\hat k$

applied force is given as

$\vec F = F_y \hat j + F_z \hat k$

now we will have

$\tau = (-L \hat k) \times (F_y \hat j + F_z \hat k)$

$\tau = L F_y \hat i$