Acetaldehyde is an organic compound (a compound containing C atoms) composed of a carbonyl group. On the other hand, a carbonyl group is a functional group containing C = O. The hybrid orbitals of a compound determines the number pi and s orbitals in the electronic configuration. For a single bond, there are two s orbitals. For double bonds, on the other hand, the number of s orbital bond is 1 while the number of pi bonds is 2. For triple bonds, there are three pi bonds present in the cloud.
Thus for a c = O bond, the atomic orbital configuration is sp3 containing 1 s orbital and 2 pi bonds.
Answer:
Explanation:
A <em>combustion reaction</em> is the reaction with oxygen along with the release of energy in form of heat or light.
Organic compounds (like CH₄) undergo combustion forming water and CO₂.
The combustion reaction of CH₄ is:
Hence, the first equation from the choices is not showing the combustion reaction of CH₄.
Not only organic compounds can undergo combustion. Metals and no metals can undergo combustion, i.e. metals and no metals can react with oxygen releasing light or heat.
The reaction of copper and oxygen (second choice) is a combustion reaction:
The formation of water (2H₂ + O₂ → 2H₂O) is other example of a combustion reaction where no organic compounds are involved.
On the other hand, the other two equations from the choice list are not reactions with oxygen, so they do not show combustion reactions.
<span>Answer:
It depends on what came after "0.5440 M H...".
If it was a monoprotic acid, like HCl, the calculation would go like this:
(55.25 mL) x (0.5440 M acid) x (1 mol KOH / 1 mol acid) / (0.2450 M KOH) =
122.7 mL KOH
If it was a diprotic acid, like H2SO4, like this:
(55.25 mL) x (0.5440 M acid) x (2 mol KOH / 1 mol acid) / (0.2450 M KOH) =
245.4 mL KOH
If it was a triprotic acid, like H3PO4, like this:
(55.25 mL) x (0.5440 M acid) x (3 mol KOH / 1 mol acid) / (0.2450 M KOH) =
368.0 mL KOH</span>
g = 19.6 N/2.2 kg. g = 8.9 m/s2. 7.
