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Kryger [21]
2 years ago
4

You throw a tennis ball (mass 0.0570 kg) vertically upward. It leaves your hand moving at 15.0 m/s. Air resistance cannot be neg

lected, and the ball reaches a maximum height of 8.00 m. By how much does the total mechanical energy decrease from when the ball leaves your hand to when it reaches its maximum height?
Physics
1 answer:
belka [17]2 years ago
5 0

Answer: It decreases 1.94 J.

Explanation:

At starting level, if we choose this height as our gravitational potential energy reference level, all the energy is kinetic:

E1 = K1 = 1/2 mv² = 1/2 . 0.057 Kg. 15² (m/s)² = 6.41 J

When it arrives to the maximum height (in this case, 8.0 m), all the energy has become gravitational potential energy, as the ball is at  rest just before starting to fall:

E2 = U2 = m.g.h = 0.057 kg. 9.8 m/s². 8.0 m = 4.47 J

The difference between these values is due to the effect of the air resistance, and can be expressed as follows:

ΔE = 6.41 J - 4.47 J = 1.94 J

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B

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The gravitational field on the surface of the earth is stronger than that on the surface of the moon. If a rock is transported f
topjm [15]

Answer: Weight only.

Explanation: Mass is a measure of the amount of matter in an object. Weight is a measure of the gravitational force exerted on the material in a gravitational field. Mass and weight are proportional to each other, with the acceleration due to gravity as the proportionality constant.

If a rock is transported from the moon to the earth, the mass is constant for the object but the weight will depends on the locations of the object. The gravitational acceleration would change because the radius and mass of the Moon is different from the Earth.

Thus, the object (rock) has <em>mass, m</em> both on the surface of the Earth and the surface of the Moon; but it will <em>weight</em> much less on the surface of the Moon as the Moon's surface gravity is 1/6 of the Earth.

4 0
2 years ago
The diagram shows the electric field due to point charge Q. Which statements are correct? Check all that apply.
Bess [88]

Answer:

The <em>correct</em> statements  are:

  • <em>A. The electric field is nonuniform.</em>
  • <em>D. Charge Q is positive.</em>
  • <em>E. If charge A moves toward charge Q, it must be a negative charge</em>

Explanation:

The answer choices are:

  • A. The electric field is nonuniform.
  • B. The electric field is uniform.
  • C. Charge Q is negative.
  • D. Charge Q is positive.
  • E. If charge A moves toward charge Q, it must be a negative charge.
  • F. If charge A moves toward charge Q, it must be a positive charge.

<h2>Solution</h2>

The <em>electric field</em> is the electrostatic force per unit of charge,  

         \vec E=\dfrac{\vec F}{Q}

around around a charge, where another charge would experience the electrostatic force.

The electric field lines are shown in a diagram with arrows ditributed radially away from a positive charge and radially toward a negative charge.

Since the arrows are away from Q, Q is a positive charge: <em>statement D.</em>

Since the size of the arrows decreases as you move away  from Q the stregth of the field is not uniform: <em>statement A.</em>

Since the charge Q is positive, a negative charge would be attracted toward it: <em>statement E.</em>

4 0
2 years ago
Consider a variety of colors of visible light (say 400 nm to 700 nm) falling onto a pair of slits.
babymother [125]

Answer:

Explanation:

The relationship between angle and wavelength for maxima and minima in Young's double slit experiment is given by

For constructive interference

d\sin \theta =m\lambda

For Destructive interference

d\sin \theta =(m+\frac{1}{2})\lambda

where \lambda =wavelength

d=slit\ width

m=order of maxima and minima

for second order maxima i.e. m=2

For smallest separation taking \lambda =400 nm, \theta =90^{\circ}

d\sin 90=2\times 400\times 10^{-9}

d=0.8\times 10^{-6}

d=0.8\mu m

   

6 0
2 years ago
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