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Alexxandr [17]
2 years ago
3

Indicate whether each of the following chemical conversions REQUIRES an oxidizing agent (O), a reducing agent (R), or neither (N

). a) NO31- NH3 b) PO33- PO43- c) AgCl Ag1+ + Cl1- List the letter of your answers in order and separated by commas. For example, O,R,N
Chemistry
1 answer:
grin007 [14]2 years ago
5 0

Answer:

The answer is: R, O, N

Explanation:

Oxidizing agent is a chemical species that carries out the <u>oxidation of another chemical species</u> and gets reduced itself .

Whereas, reducing agent is a chemical species that carries out the <u>reduction of another chemical species </u>and gets oxidized itself .

a)  NO₃⁻ → NH₃

In the nitrate ion ( NO₃⁻), the oxidation state of the nitrogen (N) atom is +5.

Whereas, the oxidation state of the nitrogen (N) atom in ammonia (NH₃) is -3.

Thus in this reaction, <u>nitrogen atom is getting reduced from +5 to -3 oxidation state</u>.

<em><u>Therefore, it requires a </u></em><em><u>reducing agent (R)</u></em><em><u>.</u></em>

b) PO₃³⁻ → PO₄³⁻

In the phosphite ion ( PO₃³⁻), the oxidation state of the phosphorus (P) atom is +3.

Whereas, the oxidation state of the phosphorus (P) atom in phosphate ion (PO₄³⁻) is +5.

Thus in this reaction, <u>phosphorus atom is getting oxidized from +3 to +5 oxidation state.</u>

<em><u>Therefore, it requires an </u></em><em><u>oxidizing agent (O)</u></em><em><u>.</u></em>

c)  AgCl → Ag⁺ + Cl⁻

The oxidation state of silver (Ag) atom and chlorine (Cl) atom is +1 and -1, respectively.

In this reaction, the oxidation states of silver (Ag) atom and chlorine (Cl) atom <u>remains unchanged.</u>

<em><u>Therefore,</u></em><u> </u><em><u>it does not require a oxidizing agent or a reducing agent </u></em><em><u>(N)</u></em><em><u>.</u></em>

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How does the equilibrium change to counter the removal of A in this reaction? A + B ⇌ AB
atroni [7]

 To counter the removal of A  the  equilibrium  change by <u>s</u><em>hifting toward the left</em>


<em>          </em><u><em>explanation</em></u>

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Isopentyl acetate (C7H14O2), the compound responsible for the scent of bananas, can be produced commercially. Interestingly, bee
lora16 [44]

Answer:

The answer to your question is:

a) 4.64 x 10 ¹⁵ molecules

b) 9.28 x 10 ¹⁵ atoms of O2

Explanation:

MW C7H14O2 = 84 + 14 + 32 = 130 g

a)        130 g of C7H14O2 ---------------- 1 mol of C7H14O2

           1 x 10 ⁻⁶ g              ---------------      x

           x = 7.7 x 10 ⁻⁹ mol

          1 mol of C7H14O2   --------------   6 .023 x 10 ²³ molecules

          7.7 x 10⁻⁹ mol          --------------    x

          x = 4.64 x 10¹⁵ molecules

b)      130 g of C7H14O2   ----------------   1 mol of C7H14O2

         1 x 10⁻⁶  C7H14O2   -----------------     x

         x = 7.7 x 10 ⁻⁹ mol of C7H14O2

        1 mol of C7H14O2    ---------------   2 mol of O2

        7.7 x 10 ⁻⁹                 ----------------   x

         x = 1.54 x 10⁻⁸ mol of O2

       1 mol of O2 -----------------  6.023 x 10 ²³ atoms

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8 0
2 years ago
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Leokris [45]
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Now we divide out each element's atomic mass (from the periodic table). it's okay if they're approximated from the decimal answer.
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H: 36.416 ÷ 1.008 ≈36
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Therefore, the molecular formula is C18H36O2. 

The empirical formula would be found by dividing out all factors of those subscript numbers. In our case, all of them can be divided by 2. The empirical formula would be C9H18O




7 0
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