Question

Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. Each elevator has a mass of 1,000 kg.
Calculate the work done by each motor. (Express answer in scientific notation.)

a.not enough information provided to determine this answer
b.1.0 x 104 J
c.9.8 x 104 J
d.9.8 x 105 J

Answer 1

The work done by each motor is c) $9.8\cdot 10^4 J$

Explanation:

The work done when lifting an object is equal to the change in gravitational potential energy of the object:

$W=mg \Delta h$

where

m is the mass of the object

g is the acceleration of gravity

$\Delta h$ is the change in height of the object

In this problem, each motor is lifting one elevator, so the mass of each elevator is

m = 1000 kg

and we have

$g=9.8 m/s^2$

$\Delta h = 10 m$

Therefore, the work done by each motor is

$W=(1000)(9.8)(10)=9.8\cdot 10^4 J$

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