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natima [27]
2 years ago
6

A 4.99 m long rod of negligible weight is attached on one end to a ball joint which allows the rod to rotate in all directions.

The free end of the rod points 26◦ above the eastward horizontal direction. A 62.5 N force directed vertically Down is applied at the rod’s free end. What is the direction of the torque due to this force (relative to the pivot end of the rod)?
Physics
1 answer:
Aleksandr [31]2 years ago
6 0

Answer:

The answer is 91.18 Nm

Explanation:

Solution

Recall that

The length of the rod = 4.99 m

∅ = 26°

Force = 62.5N

Now,

T = r * F

The direction of the torque will be in horizontally northward

The torque magnitude is  T =r F sin θ

where ∅ will be the angle between r + F  θ= 163°

Therefore,

T = 4.99 * 62.5 * sin 163

T =91.18 Nm

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Answer:

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To solve this problem we will apply the concepts related to the kinematic equations of linear motion. From them we will consider speed as the distance traveled per unit of time. Said unit of time will be cleared to find the total time taken to travel the given distance. Later with the calculated average times and distances, we will obtain the average speed.

PART A)

The time taken to travel a distance of 250km with a speed of 95km/h is

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t = \frac{250km}{95km/h}

t = 2.63h

Time taken for the lunch is

t = 1h

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t = \frac{250}{55}

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The total time taken is

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t = 2.63+1+4.54

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2 years ago
Determine whether each substance will sink or float in corn syrup, which has a density of 1.36 g/cm3. Write “sink” or “float” in
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Answer:

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Explanation:

Below is an attachment containing the solution.

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