A string is wrapped around a pulley of radius 0.05 m and moment of inertia 0.2 kg-m2. If the string is pulled with a force F , t
1 answer:
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Answer:
Jari
Explanation:
The question requires to know who is traveling faster. This is done by comparing the gradients. The steeper the slope (high gradient), the faster the speed and vice versa.
From Jari's line, the starting point is (0, 0) and another point is (6, 7)
The gradient being change in y to change in x
Change in y=7-0=7
Change in x=6-0=6
Slope is 7/6
For Jade, first point is (0, 10) then another point is (6, 16)
Change in y=16-10=6
Change in x=6-0=6
Slope is 6/6=1
Clearly, 7/6 is greater than 6/6 or 1 hence Jari is faster than Jade
Answer:
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Explanation:
The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is
K= constant depends on the system of units used.
W= weight =485 g
D= density =7.9 g/cm³
A = exposed specimen area =100 in² =6.452 cm²
K=534 to give CPR in mpy
K=87.6 to give CPR in mm/yr
mpy
=37.4mpy
mm/yr
=0.952 mm/yr
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Answer:
The value is
Explanation:
From the question we are told that
The Coulomb constant is
The charge on the electron/proton is
The mass of proton
The mass of electron is
Generally for the electron to be held up by the force gravity
Then
Electric force on the electron = The gravitational Force
i.e