Three factors that affect the solubility of a substance are pressure, the type of solvent, and volume.

A metallurgist reacts 320.0 grams of 75.0% by mass silver nitrate solution with an excess of copper metal. How many grams of sil

denpristay [2]

Answer:

= 152.40 g

Explanation:

The equation for the reaction is;

Cu(s) + AgNO3 → Ag(s) + Cu(NO3)2

Mass of silver nitrate = 320.0 g × 0.75

= 240.0 g

Molar mass of silver nitrate = 169.87 g/mol

Therefore;

Moles of silver nitrate = 240.0 g/169.87 g/mol

= 1.413 moles

Mole ratio of Silver nitrate to silver metal = 1 : 1

Therefore, moles of silver metal = 1.413 moles

Hence;

Mass of silver metal = 1.413 moles × 107.868 g/mol

4 0

2 years ago

Consider the balanced equation below. 4NH3 + 3O2 --> 2N2 + 6H2O What is the mole ratio of NH3 to N2?

AURORKA [14]

The balanced equation given is:
4NH3 + 3O2 .....> 2N2 + 6H2O

From this equation, we can note that 4 moles of NH3 are required to produce 2 moles of N2.

Therefore, the mole ratio of NH3 to N2 is 4:2 which can be simplified into 2:1

4 0

2 years ago

Read 2 more answers

The halogens, alkali metals, and alkaline earth metals have __________ valence electrons, respectively.

natima [27]

The valence electrons are as follows for these groups of elements:

Halogen- SEVEN (halogens are group 7 elements that need one electron for the octet rule to be achieved)

Alkali Metals - ONE (these are group one elements that lose a single electron to form an octet and cation)

Alkaline Earth Metals - TWO (group two elements that lose two electrons to form 2+ cations)

8 0

2 years ago

A 1.87 L aqueous solution of KOH contains 155 g of KOH . The solution has a density of 1.29 g/mL . Calculate the molarity ( M ),

lbvjy [14]

Answer:

[KOH] = 1.47 M

[KOH] = 1.22 m

KOH = 6.86 % m/m

Explanation:

Let's analyse the data

1.87 L is the volume of solution

Density is 1.29 g/mL → Solution density

155 g of KOH → Mass of solute

Moles of solute is (mass / molar mass) = 2.76 moles.

Molarity is mol/L → 2.76 mol / 1.87 L = 1.47 M

Let's determine, the mass of solvent.

Molality is mol of solute / 1kg of solvent

We can use density to find out the mass of solution

Mass of solution - Mass of solute = Mass of solvent

Density = Mass / volume

1.29 g/mL = Mass / 1870 mL

Notice, we had to convert L to mL, cause the units of density.

1.29 g/mL . 1870 mL = Mass → 2412.3 g

2412.3 g - 155 g = 2257.3 g of solvent

Let's convert the mass of solvent to kg

2257.3 g / 1000 = 2.25kg

2.76 mol / 2.25kg = 1.22 m (molality)

% percent by mass = mass of solute in 100g of solution.

(155 g / 2257.3 g) . 100g = 6.86 % m/m

5 0

2 years ago

Plasmid DNA and a gene of interest are cut with the enzyme PpuMI. Write a possible sequence of bases for the sticky end of the g

nasty-shy [4]

Answer:

5' RG GWCCY 3'

3' YCCWG GR 5'

Explanation:

The enzyme PpuMI is a restriction endonuclease enzyme, it has a specific recognition site where it cut the DNA. The source of the enzyme is from an E. coli strain that carries the PpuMI gene from Pseudomonas putida (R. Morgan).

The enzyme PpuMI recognizes specific sequence with palindrome arrangement. It target the sequence 5' RGGWCCY 3'

target Sequence: 5' RGGWCCY 3'

3' YCCWGGR 5'

The enzyme cleavage point is at:

5' RG^GWCCY 3'

3' YCCWG^GR 5'

The product of the cleavage will give a sticky end Cleavage:

5' RG GWCCY 3'

3' YCCWG GR 5'

Note: R stands for purines (adenine and guanine). Y stands for pyrimidines (cytosine, thymine, and uracil). And W represents adenine or thymine.

5 0

2 years ago