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Sveta_85 [38]
2 years ago
9

If MnSO4 → MnO+SO3 is not a synthesis reaction, then what type of reaction is it?

Chemistry
2 answers:
mezya [45]2 years ago
8 0

Answer: It would be decomposition :)

e-lub [12.9K]2 years ago
3 0

Answer:

MnSO₄ → MnO+SO₃ is a <u><em>decomposition</em></u> reaction.

Explanation:

In a decomposition reaction, a single substance breaks down or breaks down, producing two or more different substances. In other words, decomposition reactions are those that form two or more substances from a compound. In this reaction the atoms that form a compound are separated to give the products according to the formula:

AB → A + B

This type of reactions can occur spontaneously or caused by certain external factors, such as heat, that promote the breakdown of the molecule into simpler substances.

There are 3 types of decomposition reactions, depending on the external factor that causes the reaction:

  • If the decomposition is caused by a catalyst, it is called catalysis.
  • If the decomposition occurs by the application of heat it is called thermal decomposition.
  • If the decomposition is produced by the application of electric current, it is called electrolytic decomposition or electrolysis.

Then <u><em>MnSO₄ → MnO+SO₃ is a decomposition reaction.</em></u>

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A sample of gas contains 0.1800 mol of CO(g) and 0.1800 mol of NO(g) and occupies a volume of 23.2 L. The following reaction tak
baherus [9]

Answer:

The volume of the sample is 17.4L

Explanation:

The reaction that occurs requires the same amount of CO and NO. As the moles added of both reactants are the same you don't have any limiting reactant. The only thing we need is the reaction where 4 moles of gases (2mol CO + 2mol NO) produce 3 moles of gases (2mol CO2 + 1mol N2). The moles produced are:

0.1800mol + 0.1800mol reactants =

0.3600mol reactant * (3mol products / 4mol reactants) = 0.2700 moles products.

Using Avogadro's law (States the moles of a gas are directly proportional to its pressure under constant temperature and pressure) we can find the volume of the products:

V1n2 = V2n1

<em>Where V is volume and n moles of 1, initial state and 2, final state of the gas</em>

Replacing:

V1 = 23.2L

n2 = 0.2700 moles

V2 = ??

n1 = 0.3600 moles

23.2L*0.2700mol = V2*0.3600moles

17.4L = V2

<h3>The volume of the sample is 17.4L</h3>
8 0
1 year ago
PLZ HELP!!! ILL MARK BRAINLIEST!!! You read an article written by an amateur ghost hunter. It includes the following paragraph.
djverab [1.8K]

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4 0
2 years ago
Read 2 more answers
Determine the equilibrium constant, keq, at 25°c for the reaction 2br– (aq) + i2(s) br2(l) + 2i– (aq).
Travka [436]
Electrochemical cell representation for above reaction is,

Br-/Br2//I2/I-

Reaction at Anode: Br2 + 2e-   →    2Br-               (1)
Reaction at Cathode: 2I-            →  I2   + 2e-          (2)

Standard reduction potential for Reaction 1 =  Ered(anode) = 1.066 v
Standard reduction potential for Reaction 2 = Ered(cathode) = 0.535 v

Eo cell = Ered(cathode)  -  Ered(anode)
            = 0.535 - 1.066
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Now, we know that ΔGo = -nF (Eo cell)        ..............(3)
Also, ΔGo = RTln(K)         ..........(4)

Equation 3 and 4 we get,

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5 0
2 years ago
Determine the molar mass of freon–11 gas if a sample weighing 0.597 g occupies 100. cm3 at 95°c, and 1,000. mmhg (r = 0.08206 l
Stells [14]
We can first find the number of moles using the ideal gas law equation,
PV = nrT
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n - number of moles 
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T - temperature in Kelvin - 95 °C + 273 = 368 K
substituting these values 
1.32 atm x 100 x 10⁻³ L = n x 0.08206 LatmK⁻¹mol⁻¹ x 368 K
n = 0.00437 mol

molar mass can be determined as follows
molar mass = mass present / number of moles 
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Tom [10]

Answer:

Explanation:

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2 years ago
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