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2 years ago

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Part A What is the function of the nuclear pore complex found in eukaryotes? What is the function of the nuclear pore complex fo

und in eukaryotes? It synthesizes the proteins required to copy DNA and make mRNA. It assembles ribosomes from raw materials that are synthesized in the nucleus. It selectively transports molecules out of the nucleus but prevents all inbound molecules from entering the nucleus. It regulates the movement of proteins and RNAs into and out of the nucleus.

1 answer:

34kurt2 years ago

8 0

Answer:

It regulates the movement of proteins and RNAs into and out of the nucleus

Explanation:

The nuclear pore complex are protein channels connecting the outer membrane of the nucleus to the inner membrane of the nucleus. They securely regulates the almost all of the transport of protein and RNAs into and out of the nucleus.

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A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

Ierofanga [76]

2.88 m/s is the velocity afterward.

Explanation:

By using the law of conservation of momentum

Initial momentum = final momentum

$\mathrm{m}_{1} \mathrm{u}_{1}+\mathrm{m}_{2} \mathrm{u}_{2}=\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right) \times \mathrm{v} \text { equation }(1)$

$\mathrm{m}_{1}=91.5 \mathrm{kg} \text { is the mass of the first player }\mathrm{m}_{2}=63.5 \mathrm{kg}$

$\mathrm{m}_{2}=63.5 \mathrm{kg} \text { is the mass of the second player }$

$\mathrm{u}_{1}=2.73 \mathrm{m} / \mathrm{s} \text { is the initial velocity of the first player (choosing east as positive direction) }$

$\mathrm{u}_{2}=3.09 \mathrm{m} / \mathrm{s} \text { is the initial velocity of the second player }$

v = is their combined velocity afterwards

Solving equation (1) for v

$V=\frac{m_{1} u_{2}+m_{2} u_{2}}{m_{1}+m_{2}}$

$\mathrm{V}=\frac{(91.5 \times 2.73)+(63.5 \times 3.09)}{91.5+63.5}$

$\mathrm{V}=\frac{(249.7+196.2)}{155}$

$\mathrm{V}=\frac{445.9}{155}$

V = 2.88 m/s

Therefore the velocity afterward is <u>2.88 m/s</u>.

7 0

2 years ago

Suppose an acorn with a mass of 3.17 g falls off a tree. At a particular moment during the fall, the acorn has a kinetic energy

8090 [49]

Answer:

potential energy decrease and kinetic energy increases.

Explanation:

the law of conservation of energy says that the total energy of a system is conserved, then:

$E_ki +E_pi = E_kf+E_pf$

where $E_{ki}$ is the initial kinetic energy, $E_{pi}$ is the initial potential energy, $E_{kf}$ is the final kinetic energy and $E_{pf}$ is the final potential energy.

so, when the acorn fall the final potential energy is going to decrease because the potential energy is equal to:

$E_p = mgh$

Where m is the mass, g the gravity and h the height.

Therefore, in order to fullfil with the law of conservation of energy is necesary that the final kinetic energy increase.

Now, we know that the kinetic energy is equal to:

$E_k = \frac{1}{2}mv^2$

where v is the velocity, so, it means that the velocity of the acorn is going to increase.

4 0

2 years ago

A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.

Gekata [30.6K]

As per the question, the point charge is given as [q] = 6.8 C

The velocity of the charged particle [v] = $6.5*10^{4}\ m/s$

The magnetic field [B] = 1.4 T

The angle made between magnetic field and velocity $[\theta]$ = 15 degree.

We are asked to calculate the magnetic force experienced by the charged particle.

The magnetic force experienced by the charged particle is calculated as -

Magnetic force $\vec F=q(\ \vec V \times \vec B)$

i.e F = $=qVBsin\theta$

$=6.8*6.5*10^{4}*1.4*sin15$

$=61.88*10^{4}sin15$

$=61.88*10^4*0.2588\ N$

$=16.016*10^4\ N$

$=1.6*10^5\ N$

Hence, the force experienced by the charged particle is C i.e $1.6*10^5 N$

4 0

2 years ago

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What is a manifest function of a married father joining the military

katovenus [111]

Answer:

Explanation:

Manifest- he supports his family, fights for a living. He will support his family while he fights for a living it is basically his job. By fighting in war that is what income his family will get

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2 years ago

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The air in tires can support a car because gases __________.

____ [38]

Because the air inside the tires is kept at high pressure.

In fact, the force applied by the tires upwards to counter-balance the weight of the car (pushing downwards) is
$F=pA$
where p is the pressure of the air inside the tires and A is the area of contact between the tire and the car. Therefore, a higher pressure means a larger force F, and eventually if the pressure p is higher enough the force F will be large enough to counterbalance the weight of the car.

8 0

2 years ago