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2 years ago

Which of the following models shows how unpredictable electrons are?

Physics

2 answers:

777dan777 [17]2 years ago

8 0

Answer:

on edge

Explanation:

Fantom [35]2 years ago

7 0

The exact location of electrons in electron shells of atoms cannot be exactly ascertained. This is why VSPER atomic models represent the position of electrons (s, p, d, & f) using the probability of where they would most be expected to be found.

Explanation:

This is because merely observing electrons changes their behavior. Remember that to observe something one has to shine light on it so it bounces back to the eye. Due to the negligible mass of electrons, mere photons of light will change their direction of movement, spin or other behaviors/properties.

Learn More:

For more on electron clouds check out;

brainly.com/question/12199882

brainly.com/question/11686000

#LearnWithBrainly

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A and B, move toward one another. Object A has twice the mass and half the speed of object B. Which of the following describes t

BARSIC [14]

Answer:D

Explanation:

Given

mass of A is twice the mass of B half the velocity of B

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and According to Newton third law of motion Force on the body A is equal to Force on body B but opposite in direction as they are action and reaction force.

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2 years ago

If a force always acts perpendicular to an object's direction of motion, that force cannot change the object's kinetic energy.

laiz [17]

This is very good conceptual question and can clear your doubts regarding work-energy theorem.
Whenever force is perpendicular to the direction of the motion, work done by that force is zero.
According to work-energy theorem,
Work done by all the force = change in kinetic energy.

here, work done = 0.
Therefore,
0=change in kinetic energy
This means kinetic energy remains constant.
Hope this helps

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2 years ago

You are asked to design a spring that will give a 1160-kg satellite a speed of 2.50 m>s relative to an orbiting space shuttle

Tju [1.3M]

Given:
m = 1160 kg
g = 9,81 m/s²
v = 2.5 m/s

Unknown:
k spring constant
x spring compression

1. equation to use is Newton's 2nd law and Hook's law:
$F = ma = m(5g) = |kx|$
2. equation to use, the energy of the spring must equal the energy of the satellite:
$\frac{1}{2} kx^2 = \frac{1}{2} mv^2$
Combinig the two equations:
$\frac{1}{2} mv^2 = \frac{1}{2} m(5g)x \\ v^2 = 5gx \\ x = \frac{v^2}{5g} \\ \\ k = \frac{m(5g)}{x} = \frac{m(5g)^2}{v^2}$

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