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2 years ago

A chemist reported that 100 gallons of a gas were available in a laboratory. Which property of the gas did the chemist report?

Chemistry

2 answers:

Cloud [144]2 years ago

6 0

Answer:

It would be volume

Explanation:

padilas [110]2 years ago

6 0

Answer:

The chemist reported a unit of volume.

Explanation:

The complete question is: A chemist reported that 100 gallons of gas were available in a laboratory which property of the gas to the chemist report?

A. Length

B. Mass

C. Temperature

D. Volume

However, regardless of the options, you can see that the gallon is a unit of volume that is used in Anglophone or influenced countries and in several Latin American countries (such as Nicaragua and Panama, among others), to measure volumes of liquids such as fuel, milk, wine or beer.

The interesting thing about this measure is that it is not the same to speak of a British gallon than a gallon in America. A US gallon equals 3,785 liters while the imperial or British gallon equals 4, 546 liters.

Then, the chemist reported a unit of volume.

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A student has a mixture of salt (NaCl) and sugar (C12H22O11). To determine the percent composition, the student measures out 5.8

ra1l [238]

Answer:

1. Net ionic equation:

Cl⁻(aq) + Ag⁺(aq) → AgCl(s)

2. Volume of 1.0M AgNO₃

41ml

Explanation:

1. Net ionic equation for the reaction of NaCl with AgNO₃.

i) Molecular equation:

It is important to show the phases:

(aq) for ions in aqueous solution
(s) for solid compounds or elements
(g) for gaseous compounds or elements

NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)

ii) Dissociation reactions:

Determine the ions formed:

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

AgNO₃(aq) → Ag⁺(aq) + NO₃⁻(aq)

NaNO₃(aq) → Na⁺(aq) + NO₃⁻(aq)

iii) Total ionic equation:

Substitute the aqueous compounds with the ions determined above:

Na⁺(aq) + Cl⁻(aq) + Ag⁺(aq) + NO₃⁻(aq) → AgCl(s) + Na⁺(aq) + NO₃⁻(aq)

iv) Net ionic equation

Remove the spectator ions:

Cl⁻(aq) + Ag⁺(aq) → AgCl(s) ← answer

2. How many mL of 1.0 M AgNO₃ will be required to precipitate 5.84 g of AgCl

i) Determine the number of moles of AgNO₃

The reaction is 1 to 1: 1 mole of AgNO₃ produces 1 mol of AgCl

The number of moles of AgCl is determined using the molar mass:

number of moles = mass in grams / molar mass

molar mass of AgCl = 143.32g/mol

number of moles = 5.84g / (143.32g/mol) = 0.040748 mol

ii) Determine the volume of AgNO₃

molarity = number of moles of solute / volume of solution in liters

1.0M = 0.040748mol / V

V = 0.040748mol / (1.0M) = 0.040748 liter

V = 0.040748liter × 1,000ml / liter = 40.748 ml

Round to two significant figures: 41ml ← answer

4 0

2 years ago

Arkeisha and Rodney are having a discussion about the correct use of the term "battery acid." Arkeisha insists that an alkaline

mote1985 [20]

Arkeisha is correct because the fluid in an alkaline battery has a ph between 7.1 and 14.0

8 0

2 years ago

9) After lab, all of Darrel’s friends looked at his data and laughed and laughed. They told him that he was 30.8% too low in the

zaharov [31]

If he was 30.8% too low, it means that he was at 69.2% of the boiling point needed. So 50o C is 69.2% of total.

In order to know what 100% is, you can divide the number by it's percentage and then multiply it by a hundred.

So: 50/30.8=1.623
1.623*100=162.3
So the correct boiling point of the liquid he was working with in the lab is 162.3 oC

3 0

2 years ago

Read 2 more answers

SEP Use Models Why does the number of electrons in each principal energy shell increase as the number of the shell increases?

zlopas [31]

Answer:

See explanation

Explanation:

The number of electrons in each principal energy shell increases as the number of shells increases because more electronic orbitals become available to accommodate the electrons.

For instance, the n= 2 level only accommodates eight electrons in the s and p orbitals whereas the n=3 level accommodates 18 electrons in s, p and d orbitals respectively.

Each principal level accommodates 2n^2 electrons where n= the principal energy shell.

4 0

1 year ago

The combustion of 0.374 kg of methane in the presence of excess oxygen produces 0.983 kg of carbon dioxide. What is the percent

anyanavicka [17]

Assuming that the combustion formula is
CH4 + 2O2 --> 2H2O + CO2,

That means for every 1 molecule of methane(CH4) there will be one molecule of carbon dioxide(CO2) produced. Methane molecular weight 16, carbon dioxide molecular weight is 44. Then the percent yield should be:
1 * (0.374/ 16) /(0.983/44)= 0.374*44/ 0.983 * 16= 104.6%

You sure the number is correct? Percent yield should not exceed 100%

5 0

2 years ago