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2 years ago

A chemist reported that 100 gallons of a gas were available in a laboratory. Which property of the gas did the chemist report?

Chemistry

2 answers:

Cloud [144]2 years ago

6 0

Answer:

It would be volume

Explanation:

padilas [110]2 years ago

6 0

Answer:

The chemist reported a unit of volume.

Explanation:

The complete question is: A chemist reported that 100 gallons of gas were available in a laboratory which property of the gas to the chemist report?

A. Length

B. Mass

C. Temperature

D. Volume

However, regardless of the options, you can see that the gallon is a unit of volume that is used in Anglophone or influenced countries and in several Latin American countries (such as Nicaragua and Panama, among others), to measure volumes of liquids such as fuel, milk, wine or beer.

The interesting thing about this measure is that it is not the same to speak of a British gallon than a gallon in America. A US gallon equals 3,785 liters while the imperial or British gallon equals 4, 546 liters.

Then, the chemist reported a unit of volume.

You might be interested in

Which of the following statements describe chemical properties?

Y_Kistochka [10]

Answer:

A. Oxygen gas supports combustion.

B. Hydrofluoric acid reacts with glass.

C. Fertilizers help to increase agricultural production.

Explanation:

Chemical properties can only be observed when a chemical change, i.e. a change in the chemical composition, occurs.

On the other hand, physical properties are observed or measured without altering the composition of the substances.

Typical examples of chemical properties are reactivity, flammability, combustion, oxidation states, acidity, among others that require to carry out a chemical reaction to be observed.

Typical examples of physical properties are freezing point, melting point, boiling point, density, solubility, corrosiveness, among others.

Thus, as for the choices you have:

A. Oxygen gas supports combustion: the only way to observe this property is by carrying out a combustion reaction, so this describes a chemical property.

B. Hydrofluoric acid reacts with glass: again, only by letting hydrofluoric acid react with glass this can be observed, so this is another example of a chemical property.

C. Fertilizers help to increase agricultural production: fertilizers are absorbed by the plants and converted by biochemical reactions, so this also describes a chemical property.

D. Water boils below 100°C on top of a mountain: boiling is a change of state, the water is H₂O and continues having the same composition after boiling, so this describes a physical property.

E. Lead is denser than aluminum: density is measured by physical media, measuring mass and volume; so this is a physical property.

4 0

2 years ago

ethylene glycol used in automobile antifreeze and in the production of polyester. The name glycol stems from the sweet taste of

Luden [163]

Answer: The empirical and molecular formula for the given organic compound is $CH_3O$ and $C_4H_{12}O_4$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=9.06g$

Mass of $H_2O=5.58g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 9.06 g of carbon dioxide, $\frac{12}{44}\times 9.06=2.47g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 5.58 g of water, $\frac{2}{18}\times 5.58=0.62g$ of hydrogen will be contained.

Mass of oxygen in the compound = (6.38) - (2.47 + 0.62) = 3.29 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{2.47g}{12g/mole}=0.206moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.62g}{1g/mole}=0.62moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{3.29g}{16g/mole}=0.206moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.206 moles.

For Carbon = $\frac{0.206}{0.206}=1$

For Hydrogen = $\frac{0.62}{0.206}=3$

For Oxygen = $\frac{0.206}{0.206}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 3 : 1

Hence, the empirical formula for the given compound is $C_1H_{3}O_1=CH_3O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 124 amu = 124 g/mol

Mass of empirical formula = 31 g/mol

Putting values in above equation, we get:

$n=\frac{124g/mol}{31g/mol}=4$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 4)}H_{(3\times 4)}O_{(1\times 4)}=C_4H_{12}O_4$

Thus, the empirical and molecular formula for the given organic compound is $CH_3O$ and $C_4H_{12}O_4$

3 0

2 years ago

A 0.2-mm-thick wafer of silicon is treated so that a uniform concentration gradient of antimony is produced. One surface contain

krek1111 [17]

Answer:

- 0.0249% Sb/cm

$-1.2465 * 10^9 \frac{atoms}{cm^3.cm}$

Explanation:

Given that:

One surface contains 1 Sb atom per 10⁸ Si atoms and the other surface contains 500 Sb atoms per 10⁸ Si atoms.

The concentration gradient in atomic percent (%) Sb per cm can be calculated as follows:

The difference in concentration = $\delta_c$

The distance $\delta_x$ = 0.2-mm = 0.02 cm

Now, the concentration of silicon at one surface containing 1 Sb atom per 10⁸ silicon atoms and at the outer surface that has 500 Sb atom per 10⁸ silicon atoms can be calculated as follows:

$\frac{\delta_c}{\delta_c} = \frac{(1/10^8 -500/10^8)}{0.02cm} *100%$

= - 0.0249% Sb/cm

b) The concentration $(c_1)$ of Sb in atom/cm³ for the surface of 1 Sb atoms can be calculated by using the formula:

$c_1 = \frac{(8 si atoms/unit cells)(1/10^3)}{(lattice parameter)^3/unit cell}$

Lattice parameter = 5.4307 Å; To cm ; we have

= $5.4307A^0* \frac{10^{-8}cm}{ A^0}$

$c_1 = \frac{(8 si atoms/unit cells)(1/10^8)}{(5.4307*10^{-8}cm)^3/unit cell}$

= $0.00499*10^{17}atoms/cm^3$

The concentration $(c_2)$ of Sb in atom/cm³ for the surface of 500 Sb can be calculated as follows:

$c_1 = \frac{(8 si atoms/unit cells)(500/10^8)}{(5.4307*10^{-8}cm)^3/unit cell}$

= $\frac{4*10^{-3}}{1.601*10^{-22}}$

= $2.4938*10^{17}atoms/cm^3$

Finally, to calculate the concentration gradient

$(\frac{\delta _c}{\delta_ x}) = \frac{c_1-c_2}{\delta_x}$

$(\frac{\delta _c}{\delta_ x}) = \frac{0.00499*10^{17}-2.493*10^{17}}{0.02}$

$= -1.2465 * 10^9 \frac{atoms}{cm^3.cm}$

8 0

2 years ago

Which undefined geometric term is described as a two-dimensional set of points that has no beginning or end?

adell [148]

Answer:

The two-dimensional set of points that has no beginning or end is described by the undefined geometric term plane.

Explanation:

There are three undefined terms in geometry:

point,
line, and
plane

They are referred as undefined terms because they are not defined in a formal way, i.e. using mathematically defined words. At the end these terms are abstractions (ideas).

The point has no dimensions, it can be represented by the tip of a sharp pencil.

The line is referred as an infinite set of joined points that extend indefinitely in one direction (from right to left, from north to south), so it has one dimension. The intersection of of two perpendicular walls is an example of what a line is.

Finally, the term to which the question is referred is the plane: an infinite set of joined points that extends in two dimensions. An example of plane is the surface of quite water. The plane does not have depth, only extension; that is why it has only two dimensions.

So, you should remember: points do not have dimensions, lines have one dimension, and planes have two dimensions.

8 0

2 years ago

a compound consists of 17.6% of hydrogen and 82.4% nitrogen. Determine the empirical formula of the compound

Wewaii [24]

17,6% + 82,6% = 100%

mass of N = 14g
mass of H = 1g

17,6% H = 17,6g H
82,4% N = 82,4g N

17,6g : 1g = 17,6 moles of H
82,4g : 14g = 5,89 moles of N

N : H = 5,89 : 17,6 ||:5,89
N : H = 1 : 2,99≈3

the empirical formula of the compound = NH₃ (ammonia)

6 0

2 years ago

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