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2 years ago

A moving ball with a momentum of 25 kg m / s collides head-on with a wall.

Physics

2 answers:

Harman [31]2 years ago

4 0

Answer: D. 1000N

Explanation:

p1 = 25 kgm/s, p2 = -25 kgm/s, t = 50 ms = 50 * 10^(-3) s = 0.05 s

change in momentum = initial momentum – final momentum

Mathematically represented as:

Δp = p1 - p2 = 25 - (-25) = 50 kgm/s

Δp = 50 kgm/s

change in momentum = Force * time interval

Mathematically represented thus:

Δp = F * Δt

Making F the subject of the equation, we have

F = Δp/Δt

F = 50/0.05

F = 1000 N

Yanka [14]2 years ago

3 0

Answer:

d 1000N

Explanation:

change in momentum = 25 -(-25) = 50

by impuls momentum theorm

F.Δt = p2 - p1

f = p2 - p1 / Δt

f = 50/50*10^-3

so f = 1000N

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A ball of mass 0.4 kg is initially at rest on the ground. It is kicked and leaves the kicker's foot with a speed of 5.0 m/s in a

yawa3891 [41]

Answer:

the answer the correct is 3

Explanation:

Let's use the relationship between momentum and momentum

I = Δp

I = m $v_{f}$ - m v₀

Let's calculate

I = 0.4 5.0 - 0

I = 2.0 N s

By Newton's law of action and reaction the force on the ball is equal to the force that the ball exerts on the foot, therefore the impulse on the foot of equal magnitude, but in the opposite direction

I = 2.0 Ns with 60°

When reviewing the answer the correct is 3

4 0

2 years ago

If Pete ( mass=90.0kg) weights himself and finds that he weighs 30.0 pounds, how far away from the surface of the earth is he

shutvik [7]

Answer: 9938.8 km

Explanation:

1 pound-force = 4.48 N

30.0 pounds-force = 134.4 N

The force of gravitation between Earth and object on the surface of is given by:

$F = \frac{GMm}{R^2} = mg$

Where M is the mass of the Earth, m is the mass of the object, R (6371 km) is the radius of the Earth.

At height, h above the surface of the Earth, the weight of the object:

$(mg)'= \frac{GMm}{(R+h)^2}$

we need to find "h"

taking the ratio of two:

$\frac{mg}{(mg)'}=\frac{(R+h)^2}{R^2}\\ \Rightarrow \frac{90kg \times 9.8 m/s^2}{134.4 N}=\frac{(R+h)^2}{R^2}\\ \Rightarrow 6.56 R^2= (R+h)^2 \Rightarrow h= (2.56-1)R\\ \Rightarrow h = 1.56 R = 1.56 \times 6371 km = 9938. 8 km$

Hence, Pete would weigh 30 pounds at 9938.8 km above the surface of the Earth.

5 0

2 years ago

A cat falls from a table of height 1.3 m. What is the impact speed of the cat?

guapka [62]

Use this formula
Vf = sqrt(2gh)

5 0

2 years ago

For a long ideal solenoid having a circular cross-section, the magnetic field strength within the solenoid is given by the equat

andrezito [222]

Answer:

Radius of the solenoid is 0.93 meters.

Explanation:

It is given that,

The magnetic field strength within the solenoid is given by the equation,

$B(t)=5t\ T$ , t is time in seconds

$\dfrac{dB}{dt}=5\ T$

The induced electric field outside the solenoid is 1.1 V/m at a distance of 2.0 m from the axis of the solenoid, x = 2 m

The electric field due to changing magnetic field is given by :

$E(2\pi x)=\dfrac{d\phi}{dt}$

x is the distance from the axis of the solenoid

$E(2\pi x)=\pi r^2\dfrac{dB}{dt}$ , r is the radius of the solenoid

$r^2=\dfrac{2xE}{(dE/dt)}$

$r^2=\dfrac{2\times 2\times 1.1}{(5)}$

r = 0.93 meters

So, the radius of the solenoid is 0.93 meters. Hence, this is the required solution.

4 0

2 years ago

Read 2 more answers

Which statement is not a good practice when working inside a computer case?

lozanna [386]

Answer:

a. be sure to hold expansion cards by the edge connectors

Explanation:

Removal of loose jewelry is a good safety practice. Also not touching a microchip with a magnetized screwdriver is also a good practice.

But holding expansion cards by the edge connectors is not a good practice, so it is the odd one in the question. Therefore answer option a provides the correct and best answer to the question

3 0

2 years ago