Answer:
True, True, False, False, False, False.
Explanation:
The refraction index of a material is given by the formula n=c/v, where c is the speed of light in vacuum and v the speed of light in the material. If a ray of light crosses a boundary between two transparent materials and the medium the ray enters has a larger index of refraction it means that in this new medium the speed of light is smaller than on the other one, and then its wavelength is also reduced since f must remain the same (and 
), otherwise there is a discontinuity on number of vibrations per second, which cannot happen. So we know that:
1) The wavelength of the light decreases as it enters into the medium with the greater index of refraction. True.
2) The frequency of the light remains constant as it transitions between materials. True.
3) The speed of the light remains constant as it transitions between materials. False.
4) The speed of the light increases as it enters the medium with the greater index of refraction. False.
5) The frequency of the light decreases as it enters into the medium with the greater index of refraction. False.
6) The wavelength of the light remains constant as it transitions between materials. False.
Answer:
70 cm
Explanation:
0.5 kg at 20 cm
0.3 kg at 60 cm
x = Distance of the third 0.6 kg mass
Meter stick hanging at 50 cm
Torque about the support point is given by (torque is conserved)
The position of the third mass of 0.6 kg is at 20+50 = 70 cm
Answer:
The answer is 91.18 Nm
Explanation:
Solution
Recall that
The length of the rod = 4.99 m
∅ = 26°
Force = 62.5N
Now,
T = r * F
The direction of the torque will be in horizontally northward
The torque magnitude is T =r F sin θ
where ∅ will be the angle between r + F θ= 163°
Therefore,
T = 4.99 * 62.5 * sin 163
T =91.18 Nm
Answer:
0.01
Explanation:
Given the data:
10.1,9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, 9.90
True value = 9.81
Mean value :
Σx / n
Sample size, n = 9
(10.1 + 9.87 + 9.76 + 9.91 + 9.75 + 9.88 + 9.69 + 9.83 + 9.90) / 9
= 88.69 / 9
= 9.854
Standard deviation (σ) :
Sqrt (Σ(X - m)² / n)
[(10.1 - 9.854)^2 + (9.87 - 9.854)^2 + (9.76 - 9.854)^2 + (9.91 - 9.854)^2 + (9.75 - 9.854)^2 + (9.88 - 9.854)^2 + (9.69 - 9.854)^2 + (9.83 - 9.854)^2 + (9.90 - 9.854)^2] / 9
Sqrt(0.113824 / 9)
Sqrt(0.0126471)
σ = 0.1124593
Standard Error = σ / sqrt(n)
Standard Error = 0.1124593 / 9
Standard Error = 0.0124954
Standard Error = 0.01 ( 1 significant digit)
Answer:
The energy required to extend the pen is 7.2 mJ.
Explanation:
Given that,
Length = 1.8 cm
Spring constant = 300 N/m
Spring is compressed = 1.0 mm
Again, Compressed = 6.0 mm
Total compressed = 1.0+6.0 = 7.0 mm
We need to calculate the required energy
The energy required is equal to the change in spring potential energy
Put the value into the formula
Hence, The energy required to extend the pen is 7.2 mJ.
