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Alenkinab [10]
2 years ago
12

How does gravity affect the density and physical features of earth’s layers?

Physics
1 answer:
Natalka [10]2 years ago
5 0

Answer:

The atmosphere and Earth's interior are layered by density. The differentiation between these layers is due to processes that took place during the early stages of Earth's formation (ca. 4.5 billion years ago). At this time, melting would have caused denser substances to sink toward the center while less-dense materials would have migrated to the crust.

Gravity pulls more strongly on denser materials so denser materials are at the center of things. The lowest layer of the atmosphere is denser than the upper layer. Earth's liquid metal oure has convection, which generates the magnetic field.

Explanation:

Gravity pulls more strongly on denser materials so denser materials are at the center of things. The lowest layer of the atmosphere is denser than the upper layer. Earth's liquid metal core has convection, which generates the magnetic field.

The five physical layers are the lithosphere, asthenosphere, mesosphere, outer core, and inner core.  Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core.

The layers of the Earth are responsible for the formation of our continents. Earthquakes can be important because of energy (seismic energy) released. The atmosphere and Earth's interior are layered by density. Gravity pulls more strongly on denser materials so denser materials are at the center of things. Earth's core, at its center, is denser than its crust. The lowest layer of the atmosphere is denser than the upper layer.

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When photons with a wavelength of 310. nm strike a magnesium plate, the maximum velocity of the ejected electrons is 3.45 105 m/
Kisachek [45]
This problem can be solved based on the rule of energy conservation, as the energy of the photon covers both the energy needed to overcome the binding energy as well as the energy of ejection.

The rule can be written as follows:
energy of photon = binding energy + kinetic energy of ejectection
(hc) / lambda = E + 0.5 x m x v^2 where:
h is plank's constant = 6.63 x 10^-34 m^2 kg / s
c is the speed of light = 3 x 10^8 m/sec
lambda is the wavelength = 310 nm
E is the required binding energy
m is the mass of photon = 9.11 x 10^-31 kg
v is the velocity = 3.45 x 10^5 m/s

So, as you can see, all the parameters in the equation are given except for E. Substitute to get the required E as follows:
(6.63x10^-34x3x10^8)/(310x10^-9) = E + 0.5(9.11 x 10^-31)(3.45x10^5)^2
E = 6.41 x 10^-16 joule

To get the E in ev, just divide the value in joules by 1.6 x 10^-19
E = 4.009 ev
3 0
2 years ago
You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase the t
lina2011 [118]

Answer:

W = 172.5 J

Explanation:

given,                                    

mass of the fruit crate = 14.5 kg

initial velocity to lift = 0.500 m/s

increase in the tension = 150 N

lift of crate = 1.15 m                  

work done by the tension = ?        

work done  = force x displacement

W = F s cos θ                                

θ = 0°                                    

W = F s x cos 0                                  

W = 150 x 1.15 x 1                

W = 172.5 J                                      

Work done on the crate by the tension force = W = 172.5 J

5 0
2 years ago
explain why the impact of one heavy stone would produce waves with higher amplitude than the impact of the light stone would
DerKrebs [107]
The heavy stone would produce waves with a higher amplitude, rather than the smaller stone, because since the stone is heaver its going to have a grater impact and displace more water to create a bigger wave.
5 0
2 years ago
A capacitor with C = 6.00 μF is fully charged by connecting it to a battery that has emf 50.0 V. The capacitor is disconnected f
Arte-miy333 [17]

Answer:

1.99×10^-4coulombs

Explanation:

The charge (Q) across the resistor the directly proportional to the voltage (V) where capacitance of the capacitor(C) is the proportionality constant. Mathematically, Q = CV

If V is the voltage across the resistor, V = IR (according to ohm's law) where I is the current in the resistor and R is the resistance.

We need to calculate the voltage on the resistor first when 0.18A current is passed through it.

V = 0.18 × 185

V = 33.3Volts

The charge Q on the resistor will be;

Q = CV

Were C = 6.00 μF, V = 33.3

Q= 6×10^-6 ×33.3

Q = 0.0001998

Q= 1.99×10^-4Coulombs

4 0
2 years ago
The difference between the two molar specific heats of a gas is 8000J/kgK. If the ratio of the two specific heats is 1.65, calcu
Serjik [45]

Answer:

sorry

Explanation:

pls search on google

4 0
2 years ago
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