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KiRa [710]
2 years ago
14

Water is placed outside at 298 K overnight. Which statement best describes what would happen?a)298 K converts to -24.9 °C, so th

e water would freezeb)298 K converts to 24.9 °C, so the water would remain in its liquid statec)298 K converts to 24.9 °C, so the water would freeze
Chemistry
1 answer:
user100 [1]2 years ago
7 0

Answer: b)298 K converts to 24.9 °C, so the water would remain in its liquid state

Explanation: Kelvin is an absolute temperature scale, that means that 0K (zero Kelvin) is the lowest temperature possible and compare to Celsius scale the change of 1 degree is the same, but 0°C is the same as 273,1K

So, in order to convert Kelvin to Celsius you have to subtract 273,1

In this case, 298K - 273,1 = 24,9°C

This temperature is room temperature, so water is in liquid state.

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An ion has 24 protons and 19 electrons. Write the symbol for this ion.
Lerok [7]

Answer:

+5

Explanation:

it hs 5 more protons thant electrons, so it has a positive charge of 5

5 0
2 years ago
A 0.72-mol sample of PCl5 is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of PCl3(g) and 0.
Sonja [21]

Answer:

Equilibrium constant for PCl_5 is 0.5

Equilibrium constant for decomposition of NO_2 is 1.79 \times 10^{-14}

Explanation:

PCl_5 dissociates as follows:

                    PCl_5 \rightleftharpoons PCl_3+Cl_2

initial          0.72 mol     0         0

at eq.     0.72 - 0.40   0.40      0.40

Expression for the equilibrium constant is as follows:

k=\frac{[PCl_3][Cl_2]}{[PCl_5]}

Substitute the values in the above formula to calculate equilibrium constant as follows:

k=\frac{[0.40/1][0.40/1]}{0.32/1} \\=\frac{0.40 \times 0.40}{0.32} \\=0.5

Therefore, equilibrium constant for PCl_5 is 0.5

Now calculate the equilibrium constant for decomposition of  NO_2

It is given that 3.3 \times 10^{-3} \% is decomposed.

NO_2 decomposes as follows:

                                  2NO_2 \rightleftharpoons 2NO + O_2

initial                            1.0 M       0           0

at eq. concentration of  NO_2   is:

[NO_2]_{eq}=1-(0.000066) = 0.999934\ M

[NO]_{eq}=6.6 \times 10^{-5}\ M

[O_2]_{eq}=3.3\times 10^{-5} = 3.3\times 10^{-5}\ M      

Expression for equilibrium constant is as follows:

K=\frac{[NO]^2[O_2]}{[NO_2]^2}

Substitute the values in the above expression

K=\frac{[6.6\times 10^{-5}]^2[3.3 \times 10^{-5}]}{[0.999934]^2} \\=1.79\times 10^{-14}

Equilibrium constant for decomposition of NO_2 is 1.79 \times 10^{-14}

8 0
2 years ago
A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calc
GrogVix [38]

<u>Answer:</u>

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is <em>(\frac {J}{Kg.K})</em>

<em>C = Q/m. ∆T</em>

<em>C – Specific heat (\frac {J}{Kg.K})</em>

<em>Q- heat energy (J)</em>

<em>M – Mass (Kg)</em>

<em>∆T- change in temperature (K) </em>

<u>Explanation:</u>

<em>Given data:</em>

<em>M= 140 g = 0.14 Kg</em>

<em>Q – 1080 Joules.</em>

<em>∆T – 98.4 – 62.2 = 36.2</em>

Substituting  the given data in Equation

<em>Specific heat of Aluminium  = \frac {1080}{(0.14 \times 36.2)} = 213.10 (\frac {J}{Kg.K})</em>

3 0
2 years ago
Read 2 more answers
If the 3.90 m solution from Part A boils at 103.45 ∘C, what is the actual value of the van't Hoff factor, i? The boiling point o
erma4kov [3.2K]
<span>Some of the solutions exhibit colligative properties. These properties depend on the amount of solute dissolved in a solvent. For boiling point elevation, we calculate the increase in temperature by the equation:

</span><span>ΔT(boiling point)  = (Kb)mi

where Kb is a constant, m is the molality of the solution, i is the van't Hoff factor. 

From the given data, we can easily calculate for i as follows:

</span>ΔT(boiling point)  = (Kb)mi
103.45 - 100  = (0.512)3.90i
i = 1.73 <-------van't Hoff factor
7 0
2 years ago
The image shows a wheel that's wound up and released. The wheel moves up and down as shown. Identify the position of the wheel w
Lesechka [4]

Explanation:

Since the wheel moves up and down, the position that represents the potential energy is that which has the maximum height from the ground.

Potential energy is the energy at rest of a body.

It is given as:

      Potential energy = m x g x h

m is the mass of the body

g is the acceleration due to gravity

h is the height of the body

We can see that mass and height are directly related to the potential energy a body exerts.

The higher the wheel from ground, the higher its potential energy.

learn more

Potential energy brainly.com/question/10770261

#learnwithBrainly

7 0
2 years ago
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