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Aleksandr-060686 [28]
2 years ago
10

An automobile travelling on a straight, level road has an initial speed v when the brakes are applied. In coming to rest with a

constant acceleration, it travels a distance x. How far would the automobile travel in coming to rest if it had the same acceleration but an initial speed 2v ? a. 1/4x. b. 1/2x. c. x. d. 2x. e. 4x.
Physics
1 answer:
WITCHER [35]2 years ago
3 0

Answer:

a. 1/4X

Explanation:

As this is an uniformly accelerated rectilinear motion, we are able to use the following formulas, that link acceleration (a), speed (V), time (t) and distance (X):

V = at and X = 1/2at²

Combining both formulas, we get: V = √(2aX )

Now, if we consider both situations stated on this problem :

- Condition 1 : X₁ , V1₁

- Condition 2: X₂, V₂ = 2V₁

Finally : V₁ = √(2aX1 )

V2 = 2V1 = √(2aX2 )

Dividing both equations:

V1/2V1 = √[(2aX1)/(2aX2) ]

1/2 = √[(2aX1)/(2aX2)]   ⇒ (1/2)² = X₁/X₂ ⇒ 1/4 = X₁/X₂  

X2 = 1/4*X1  

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Two 8.0 Ω lightbulbs are connected in a 12 V series circuit. What is the power of both glowing bulbs?
V125BC [204]

Answer:

18 W

Explanation:

Applying,

P = V²/R.................. Equation 1

Where P = Power of both glowing bulbs, V = Voltage, R = Combined Resistance of both bulbs

Since: It is a series circuit,

Then,

R = R1+R2............. Equation 2

Where R1= Resistance of the first bulb, R2 = Resistance of the second bulb

Given: R1 = R2 = 8 Ω

Substitute into equation 1

R = 8+8

R = 16 Ω

Also Given: V = 12 V

Substitute into equation 1

P = 12²/8

P = 144/8

P = 18 W

7 0
2 years ago
This problem explores the behavior of charge on conductors. We take as an example a long conducting rod suspended by insulating
Olegator [25]

Answer:

rod end A is strongly attracted towards the balls

rod end B is weakly repelled by the ball as it is at a greater distance

Explanation:

When the ball with a negative charge approaches the A end of the neutral bar, the charge of the same sign will repel and as they move they move to the left end, leaving the rod with a positive charge at the A end and a negative charge of equal value at end B.

Therefore rod end A is strongly attracted towards the balls and

rod end B is weakly repelled by the ball as it is at a greater distance

3 0
2 years ago
What is the longest wavelength light capable of ionizing a hydrogen atom in the ground state?
Sindrei [870]

Answer:

9.12\cdot 10^{-8} m

Explanation:

The energy needed to ionize a hydrogen atom in the ground state is:

E=13.6 eV= 2.18\cdot 10^{-18}J

The energy of the photon is related to the wavelength by

E=\frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength

Solving the formula for the wavelength, we find

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{2.18\cdot 10^{-18}J}=9.12\cdot 10^{-8} m

7 0
2 years ago
Your employer asks you to build a 18-cmcm-long solenoid with an interior field of 5.8 mTmT . The specifications call for a singl
andrezito [222]

Answer:

Explanation:

The magnetic field in a solenoid is

          B = μ₀ N / L I

Where N is the number of turns, L the solenoid length and I the current

          N = B L /  μ₀  I

Let's calculate

        N = 5.8 10⁻³ 0.18 / 4 π 10⁻⁷ 1

        N = 8.3 102 laps

        N = 831 laps

Let's find the solenoid length

    For this we use a rule of proportions

                L_solenoid = Turns * wire diameter

                L_ solenoid = 831 * 0.41 10--3

                L_solenoid = 0.3407 m

We see that two turns are needed in the wire to have a length of 0.18 m

5 0
2 years ago
Consider two adjacent states, S1 and S2, that wish to control particulate emissions from power plants and cement plants; New Jer
natka813 [3]

Answer:

a. 7500

b. Yes

c. 2500

d. 7500

Explanation:

Please see attachment

7 0
2 years ago
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