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2 years ago

A sailboat accelerates from rest to a speed of 2 m/s east. Discuss direction and relative strength of the forces on the boat

Physics

1 answer:

antoniya [11.8K]2 years ago

7 0

Answer:

The direction of the force is towards the east.

The relative strength of the force acting on the boat is proportional to the acceleration acting on the boat.

Explanation:

Given data,

The initial velocity of the sailboat, u = 0 m/s

The final velocity of the sailboat, v = 2 m/s

Let, the time period of the sailboat to reach 2 m/s is, t = 4 s

The acceleration of the sailboat is given by the formula,

a = (v-u)/t

a = (2 - 0)/ 4

a = 0.5 m/s²

The direction of the force is towards the east.

The relative strength of the force acting on the boat is proportional to the acceleration acting on the boat.

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150-N box is being pulled horizontally in a wagon accelerating uniformly at 3.00 m/s2. The box does not move relative to the wag

mafiozo [28]

Answer:

the friction force on this box is closest to 45.9 N.

Explanation:

given data

Weight of the box W = 150 N

accelerating uniformly = 3.00 m/s²

coefficient of kinetic friction = 0.400

coefficient of static friction = 0.600

solution

we know box does not move relative to the wagon

we get here friction force that is express as

friction force = mass × acceleration ..............1

here mass = weight ÷ g

mass = $\frac{150}{9.8}$ = 15.3 kg

put value in equation 1 we get

friction force = 15.3 kg × 3

friction force = 45.9 N

So, the friction force on this box is closest to 45.9 N.

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2 years ago

A container is filled with an ideal diatomic gas to a pressure and volume of P1 and V1, respectively. The gas is then warmed in

lilavasa [31]

Answer:

Explanation:

The change is as follows

P₁ V₁ to 3P₁, V₁ ( constt volume ) --- first process

3P₁,V₁ to 3P₁ , 5V₁ ( constt pressure ) ---- second process

In the first process Temperature must have been increased 3 times . So if initial temperature is T₁ then final temperature will be 3 T₁

P₁V₁ = n R T₁ , n is no of moles of gas enclosed.

nRT₁ = P₁V₁

Heat added at constant volume = n Cv ( 3T₁ - T₁)

= n x 5/3 R X 2T₁ ( for diatomic gas Cv = 5/3 R)

= 10/3 x nRT₁

= 10/3x P₁V₁

In the second process, Temperature must have been increased 5 times . So if initial temperature is 3T₁ then final temperature will be 15 T₁

Heat added at constant pressure in second case

= n Cp ( 15T₁ - 3T₁)

= n x 7/3 R X 12T₁ ( For diatomic gas Cp = 7/3 R)

= 28 x nRT₁

= 28 P₁V₁

6 0

2 years ago

Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long. How long is the ot

s344n2d4d5 [400]

Answer:

The length of the longer pipe is L = 2.30 m

Explanation:

Given that:

Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long.

How long is the other pipe?

From above;

The formula for the frequency of open ended pipes can be expressed as:

$f = \dfrac{nv}{2L}$

where n = 1 ( since half wavelength exist between those two pipes)

v = 343 m/s and L = 2.08 m

Thus, the shorter pipe produces a frequency of :

$f = \dfrac{1*343}{2*2.08}$

$f = \dfrac{343}{4.16}$

$f =82.45 \ Hz$

Also; we know that the beat frequency was given as 8.0 Hz

Then,

The lower frequency of the longer pipe = ( 82.45 - 8.0 )Hz

The lower frequency of the longer pipe = 74.45 Hz

Finally;

From the above equation; make Length L the subject of the formula. Then,

The length of the longer pipe is L = $\dfrac{nv}{2f}$

The length of the longer pipe is L = $\dfrac{1*343}{2*74.45}$

The length of the longer pipe is L = $\dfrac{343}{148.9}$

The length of the longer pipe is L = 2.30 m

6 0

2 years ago

Why is the entropy change negative for ring closures?

Rom4ik [11]

Answer:ring closure result in fewer molecules

Explanation:

entropy is a measure of the amount of disorderliness in a system.

Therefore, the connection causes orderliness in the ring closure

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2 years ago

How does climate change lead to an increase in algal blooms? a. Decreased temperatures lead to an increase in phytoplankton grow

asambeis [7]

Answer;

B. Increased levels of carbon dioxide, a greenhouse gas, leads to increased phytoplankton growth.

Explanation;

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-Algae blooms have been increasing globally, and climate change may be playing a role in the increment. For instance, during the warm summer season or when water is warmer, some harmful types of algae to grow faster than other, more benign varieties.

-Additionally, the warmer surface water also prevents water from mixing vertically, allowing algae to grow thicker and faster.

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2 years ago

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