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joja [24]
1 year ago
14

A valve to a new chamber in the bottle is opened, and the gas expands to 2 x 10-3 m3. (The gas does no work in this process beca

use the gas molecules don't have anything moving to push on.) After a while, the parts of the gas re-equilibrate, without exchanging heat with the outside. What is the new temperature, T? T =
Chemistry
1 answer:
Fed [463]1 year ago
8 0

Answer:

The temperature doesn't change

Explanation:

Given that:

dU=dQ - dW

Where

  • U: internal energy
  • W: work
  • Q: heat

If the gas does no work and doesn't exchange heat with the outside there insn't a variation of the internal energy.

Internal energy is realted to the energy in the molecules, they vibration and theregore the temperature.

So, if there isn't a change in the internal energy you may say that there isn't a change in the temperature.

The increase in the volume is balanced by a decrease of the pression.

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Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0
ExtremeBDS [4]

Answer:

The freezing point will be 2.9^{0}C

Explanation:

The depression in freezing point is a colligative property.

It is related to molality as:

Depressioninfreezing point=K_{f}Xmolality

Where

Kf= 20\frac{^{0}C}{m}

the molality is calculated as:

molality=\frac{moles_{solute}}{mass_{solvent}}

moles=\frac{mass}{molarmass}=\frac{0.694}{154}=0.0045mol

massofcyclohexane=25g=0.025Kg

molarity=\frac{0.0045}{0.025}=0.18m

Depression in freezing point = 20X0.18=3.6^{0}C

The new freezing point = 6.5^{0}C-3.6^{0}C=2.9^{0}C

5 0
2 years ago
Like all equilibrium constants, Kw varies somewhat with temperature. Given that Kw is 3.31 × 10−13 at some temperature, compute
Artyom0805 [142]
Since Kw= [H⁺][OH⁻], and the concentration of both substances are the same, the equation is now Kw=[H⁺]²
So,
3.31x10⁻¹³ = [H⁺]²
Take the square root= 5.75x10⁻⁷
Then take the negative log to find the pH:
-log(5.75x10⁻⁷) = 6.25
5 0
2 years ago
A box contains equal amounts of helium, argon, and krypton (all gases) at 25 ∘c. part a consider the temperatures, masses, avera
crimeas [40]
1. What do they have in common?

As mentioned in the problem, these gases are present in equal amounts. So, that would infer that they are common in terms of their mass. Also, it is specified that the temperature is 25°C. Connected to that is the average kinetic energy, which is directly proportional. Hence, they are also common in temperature and average kinetic energy.

2. What are the differences?

They differ in type, of course. Also, they differ in average velocities which is a factor of temperature of molar mass. Since they are 3 different types of gases with different molar masses, they would also differ in their average velocities.
8 0
2 years ago
Read 2 more answers
A mixture of N2, O2, and Ar has mole fractions of 0.25, 0.65, and 0.10, respectively. What is the pressure of N2 if the total pr
s344n2d4d5 [400]

Answer:

Partial pressure of nitrogen gas is 0.98 bar.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gases.

P=p_{N_2}+p_{O_2}+p_{Ar}

p_{N_2}=P\times \chi_{N_2}

p_{O_2}=P\times \chi_{O_2}

p_{Ar}=P\times \chi_{Ar}

where,

P = total pressure = 3.9 bar

p_{N_2} = partial pressure of nitrogen gas  

p_{O_2} = partial pressure of oxygen gas  

p_{Ar} = partial pressure of argon gases  

\chi_{N_2} = Mole fraction of nitrogen gas  = 0.25

\chi_{O_2} = Mole fraction of oxygen gas  = 0.65

\chi_{Ar} = Mole fraction of argon gases = 0.10

Partial pressure of nitrogen gas :

p_{N_2}=P\times \chi_{N_2}=3.9 bar\times 0.25 =0.98 bar

Partial pressure of oxygen gas :

p_{N_2}=P\times \chi_{O_2}=3.9 bar\times 0.65=2.54 bar

Partial pressure of argon gas :

p_{N_2}=P\times \chi_{Ar}=3.9 bar\times 0.10=0.39 bar

7 0
2 years ago
The researcher performed a follow-up experiment to measure the rate of oxygen consumption by muscle and brain cells. Predict the
Naddik [55]

Answer:

Mitochondria are abundantly present in mammalian cells. Their fraction varies from tissue to tissue, ranging from <1% (volume) in white blood cells to 35% in heart muscle cells. However, mitochondria should not be thought of as single entities, but rather a dynamic network that continuously undergoes fission and fusion processes. In skeletal muscle, mitochondria exist as a reticular membrane network. The subsarcolemmal (SS) and intermyofibrillar (IMF) mitochondria are located in distinct subcellular regions, and they possess subtle differences in biochemical and functional properties that are characterized by their anatomical locations. SS mitochondria lie directly beneath the sarcolemmal membrane and the IMF mitochondria are located in close contact with the myofibril. Their different properties are likely to influence their capacity for adaptation. SS mitochondria account for 10-15% of the mitochondrial volume and this population has been shown to be more susceptible to adaptation than the IMF mitochondria. However, the IMF mitochondria were found to have higher rates of protein synthesises, enzyme activities and respiration (1).

Explanation:

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2 years ago
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