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joja [24]
2 years ago
14

A valve to a new chamber in the bottle is opened, and the gas expands to 2 x 10-3 m3. (The gas does no work in this process beca

use the gas molecules don't have anything moving to push on.) After a while, the parts of the gas re-equilibrate, without exchanging heat with the outside. What is the new temperature, T? T =
Chemistry
1 answer:
Fed [463]2 years ago
8 0

Answer:

The temperature doesn't change

Explanation:

Given that:

dU=dQ - dW

Where

  • U: internal energy
  • W: work
  • Q: heat

If the gas does no work and doesn't exchange heat with the outside there insn't a variation of the internal energy.

Internal energy is realted to the energy in the molecules, they vibration and theregore the temperature.

So, if there isn't a change in the internal energy you may say that there isn't a change in the temperature.

The increase in the volume is balanced by a decrease of the pression.

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12. The vapor pressure of water at 90°C is 0.692 atm. What is the vapor pressure (in atm) of a solution made by dissolving 3.68
luda_lava [24]

Answer : The vapor pressure (in atm) of a solution is, 0.679 atm

Explanation : Given,

Mass of H_2O = 1.00 kg = 1000 g

Moles of CsF = 3.68 mole

Molar mass of H_2O = 18 g/mole

Vapor pressure of water = 0.692 atm

First we have to calculate the moles of H_2O.

\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{1000g}{18g/mole}=55.55mole

Now we have to calculate the mole fraction of H_2O

\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }CsF}=\frac{55.55}{55.55+3.68}=0.938

Now we have to partial pressure of solution.

According to the Raoult's law,

P_{Solution}=X_{H_2O}\times P^o_{H_2O}

where,

P_{Solution} = vapor pressure of solution

P^o_{H_2O} = vapor pressure of water = 0.692 atm

X_{H_2O} = mole fraction of water = 0.938

P_{Solution}=X_{H_2O}\times P^o_{H_2O}

P_{Solution}=0.938\times 0.692atm

P_{Solution}=0.649atm

Therefore, the vapor pressure (in atm) of a solution is, 0.679 atm

5 0
2 years ago
What is the mass in grams of 6.022×1023 atoms of mass 16.00 amu?
german
16.00 g -------------- 6.02x10²³ atoms
?? g ----------------- 6.022x10²³ atoms

16.00 x (6.022x10²³) / 6.02x10²³ =

=> 16 g


7 0
2 years ago
The concentration of C29H60 in summer rainwater is 34 ppb. Find the molarity of this compound in nanomoles per liter (nM).
Naya [18.7K]

Answer: The concentration of C29H60 in nM per liter is 83,33 nM/liter

Explanation: Let's start from the ppb definition: ppb means parts per billion. In terms of concentracion measuring this means micrograms of solute per liter of solution.

The algebraic expression would be:

<em>ppb [=] micrograms of compound/liter of solution</em>

We can assume that the solvent is water. The solute is dissolved in water and both create the C29H60 solution.

For the exercise we have 34 ppb of C29H60, that means 34 micrograms of C29H60 in one liter of solution. So, since now, we have to convert the units from the initial data to the required answer.

The respective procedure is in a attached file.  

5 0
2 years ago
The chemical formula for cesium oxide is Cs2O. What is the charge of cesium? +1 +2 –1 –2
aalyn [17]
The Charge Of Cesium Is +1
5 0
2 years ago
Read 2 more answers
Consider the reaction cacn2 3 h2o → caco3 2 nh3 . how much nh3 is produced if 187 g of caco3 are produced?
shusha [124]
B ase from the reaction <span>cacn2 3 h2o → caco3 2 nh3, for every 1 mole of caco3 produced there 2 moles of nh3 being produced. to solved this, we must first convert the caco3 to moles.

mass nh3 = 187 g caco3 (1 mol caco3 / 100 g caco3 ) ( 2 mol nh3 / 1 mol caco3) ( 17 g nh3 / 1 mol nh3)

mass nh3 = 63.58 g nh3 is produced</span>
7 0
2 years ago
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