Two horizontal forces are exerted on a large crate. The first force is 317 N to the right. The second force is 173 N to the left
a. Draw a force diagram for the horizontal forces acting on the crate. b. What is the net force acting on the crate? c. The box is initially at rest. Five seconds later, its velocity is 6.5 m/s to the right. What is the crate's mass?
1 answer:
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Answer:
1) The magnetic field outside the loop is zero.
In region III the magnetic fields due to the two wire loops point in the opposite direction andhence cancel each other. Therefore the magnetic field is zero in region I, III and V
The diagram is attached
Answer:
F = - 50 N
Hence, the magnitude of resultant force is 50 N and its direction is leftwards.
Explanation:
The magnitude of the resultant force is always equal to the sum of all forces. While, the direction of resultant force will be equal to the direction of the force with greater magnitude:
considering right direction to be positive:
F₁ = Force applied on right rope = 150 N
F₂ = Force applied on left rope = 200 N
Therefore, the resultant force can be found by using these values in equation:
<u>F = - 50 N</u>
<u>Hence, the magnitude of resultant force is 50 N and its direction is leftwards.</u>