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vlabodo [156]
2 years ago
8

Isolating a variable in two equations is easiest when one of them has a coefficient of 1. Let's say we have the two equations 3A

−B=5 2A+3B=−4 and want to isolate one of the variables, such that it appears by itself on one side of the equation. Which of the following is an equation with one of the above variables isolated?
Physics
1 answer:
xxTIMURxx [149]2 years ago
3 0

Answer:

B=3A-5

Explanation:

<u>Variable Isolation</u>

It's a common practice when dealing with equations that we have to isolate one variable in terms of other variables and/or constants. The isolation of the variable usually implies adding, subtracting, multiplying or dividing by constants. The following example shows how to isolate the A:

2A+3B=-4\\\\2A=-4-3B\\\\\displaystyle A=\frac{-4-3B}{2}

We are required to find the equation where the variable has a coefficient of 1 and isolate it. The following equation fits into the description:

3A-B=5

Isolating B:

B=3A-5

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How many slices of bread did each climber have to eat to compensate for the increase of the gravitational potential energy of th
N76 [4]

Answer:

So No of slices to be consumed by each person = n = 65

Explanation:

Energy released by one slice = E1

E1=10^6\ J

h = 8850 m ; m = 79 kg ,η= 10.5%

We know that potential energy given as

u = m g h

u = 79 x 9.81 x 8850

u=6.8\times 10^6\ J

we know from the defination of efficiency that,  η= E(out)/E(in)

Now amount of PE has to be compensated, In our case, E(out) =u

0.105=\dfrac{E(out)}{E(in)}

0.105=\dfrac{6.8\times 10^6}{E(in)}

E(in)=64.76\times 10^6\ J

Let n be the number of bread slices to be consumed.

n = E(in)/E1

n=\dfrac{64.76\times 10^6}{10^6}

n=64.76

So No of slices to be consumed by each person = n = 65

3 0
2 years ago
Is it possible for two pieces of the same metal to have different recrystallization temperatures? Is it possible for recrystalli
Butoxors [25]

Answer:

Explained

Explanation:

Two pieces of the same metal can have different recrystallization temperatures if the pieces  have been cold worked to different amounts. The piece of work cold worked to greater extend will have more internal energy to drive the recrystalline process and lower recrystallization temperature.

Yes, its possible that recrystallization to take place in some regions of a part before it does in other regions of the same part if the work has been unevenly strained or if the part have different thickness at different sections.

6 0
2 years ago
If a sound with frequency fs is produced by a source traveling along a line with speed vs. If an observer is traveling with spee
Alexus [3.1K]

Answer:

457.81 Hz

Explanation:

From the question, it is stated that it is a question under Doppler effect.

As a result, we use this form

fo = (c + vo) / (c - vs) × fs

fo = observed frequency by observer =?

c = speed of sound = 332 m/s

vo = velocity of observer relative to source = 45 m/s

vs = velocity of source relative to observer = - 46 m/s ( it is taking a negative sign because the velocity of the source is in opposite direction to the observer).

fs = frequency of sound wave by source = 459 Hz

By substituting the the values to the equation, we have

fo = (332 + 45) / (332 - (-46)) × 459

fo = (377/ 332 + 46) × 459

fo = (377/ 378) × 459

fo = 0.9974 × 459

fo = 457.81 Hz

7 0
2 years ago
Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance
scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

x_{1}=\dfrac{\lambda D}{2d}

Second minima from center

x_{2}=\dfrac{3\lambda D}{2d}

The distance between the places where the intensity is zero due to the double slit effect

\Delta x_{d}=x_{2}-x_{1}

\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}

\Delta x_{d}=\dfrac{\lambda D}{d}

Put the value into the formula

\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}

\Delta x_{d}=0.015 =15\times10^{-3}\ m

\Delta x_{d}=15\ mm

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0
2 years ago
A storm is moving in quickly. The weather station reported that it is traveling west at 40 miles per hour. This information desc
shutvik [7]
Current position???????

4 0
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