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n200080 [17]
2 years ago
7

A 1500kg car traveling along a road is hit by a 0.1kgrock that creates a small crack in the car’s windshield. Which of the follo

wing describes the interaction between the windshield and the rock?a. The car exerts a force on the rock, but the rock does not exert a force on the car. b. The car exerts a force on the rock, and the rock exerts a force on the car. The two forces are not equal in magnitude. c. The car exerts a force on the rock, and the rock exerts a force on the car. The two forces are equal in magnitude.
Physics
2 answers:
Alex17521 [72]2 years ago
3 0

Answer:

The car exerts a force on the rock, and the rock exerts a force on the car. The two forces are equal in magnitude.

Explanation:

It is given that,

Mass of the car, M = 1500 kg

Mass of the rock, m = 0.1 kg

It is mentioned that a car traveling along a road is hit by a rock that creates a small crack in the car’s windshield. We need to find the correct option that describes the interaction between the windshield and the rock. We know that when one object hits another object, the force applied by object 1 on object 2 have equal and opposite reaction as per the Newton's third law of motion.

So, the car exerts a force on the rock, and the rock exerts a force on the car. The two forces are equal in magnitude. Hence, the correct option is (c).

mario62 [17]2 years ago
3 0

Answer:

The interaction between the windshield and the rock is described by

c) The car exerts a force on the rock, and the rock exerts a force on the car. The two forces are equal in magnitude.

Explanation:

Forces can be described as an interaction between two objects and always come in pairs.

We have to remember Newton's third law of motion:

If an object 1 exerts a force on object 2, then object 2 should exert a force of equal magnitude but opposite direction on object 1.

So, despite that the car has 1500 kg and the rock 0.1 kg, the force the car exerts on the rock and the force the rock exerts on the car are equal in magnitude.

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A roller coaster car drops a maximum vertical distance of 35.4 m. Determine the maximum speed of the car at the bottom of that d
marissa [1.9K]

Answer:

The maximum speed of the car at the bottom of that drop is 26.34 m/s.

Explanation:

Given that,

The maximum vertical distance covered by the roller coaster, h = 35.4 m

We need to find the maximum speed of the car at the bottom of that drop. It is a case of conservation of energy. The energy at bottom is equal to the energy at top such that :

mgh=\dfrac{1}{2}mv^2

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 35.4}

v = 26.34 m/s

So, the maximum speed of the car at the bottom of that drop is 26.34 m/s. Hence, this is the required solution.

8 0
2 years ago
A 2.0 kg block on a horizontal frictionless surface is attached to a spring whose force constant is 590 N/m. The block is pulled
SVETLANKA909090 [29]

Answer:

The  value is  v =  -0.04 \  m/s

Explanation:

From the question we are told that

   The  mass  of the block is  m  =  2.0 \ kg

   The  force constant  of the spring is  k  =  590 \ N/m

   The amplitude  is  A =  + 0.080

   The  time consider is  t =  0.10 \  s

Generally the angular velocity of this  block is mathematically represented as

      w =  \sqrt{\frac{k}{m} }

=>   w =  \sqrt{\frac{590}{2} }

=>   w = 17.18 \  rad/s

Given that the block undergoes simple harmonic motion the velocity is mathematically represented as  

         v  =  -A w sin (w* t )

=>       v  = -0.080 * 17.18 sin (17.18* 0.10 )

=>       v =  -0.04 \  m/s

7 0
2 years ago
In 1993, Ileana Salvador of Italy walked 3.0 km in under 12.0 min. Suppose that during 115 m of her walk Salvador is observed to
dexar [7]

Answer:

t = 25 seconds

Explanation:

Given that,

Distance, d = 115 m

Initial speed, u = 4.2 m/s

Final speed, v = 5 m/s

We need to find the time taken in increasing the speed.

We know that,

Acceleration, a=\dfrac{v-u}{t} ....(1)

The third equation of kinematics is as follows :

v^2-u^2=2ad\\\\\text{Put the value of a in above equation}\\\\v^2-u^2=2\times \dfrac{v-u}{t}\times d\\\\\because (a^2-b^2)=(a-b)(a+b)\\\\(v-u)(v+u)=\dfrac{2\times (v-u)d}{t}\\\\t=\dfrac{2d}{v+u}\\\\\text{Putting all the values}\\\\t=\dfrac{2\times 115}{4.2+5}\\\\t=25\ s

Hence, it will take 25 seconds to increase the speed.

6 0
2 years ago
Boiling water in a pan is a good example of convection because___.
belka [17]
Convection means that hotter and less dense fluids have a tendency to rise while colder and more dense fluids sink.

The answer would be (A)
Hot water is denser than cold water and so hot water will be above the cold water.

:D
5 0
2 years ago
Read 2 more answers
Calculate the mass of the air contained in a room that measures 2.50 m x 5.50 m x 3.00 m if the density of air is 1.29 g/dm3.53.
Law Incorporation [45]

Answer:

5.32\cdot 10^4 g

Explanation:

First of all, we need to find the volume of the room, which is given by

V=2.50 m \cdot 5.50 m \cdot 3.00 m =41.3 m^3

Now we  can find the mass of the air by using

m=dV

where

d=1.29 g/dm^3 is the density of the air

V=41.3 m^3 = 41,300 dm^3 is the volume of the room

Substituting,

m=(1.29)(41300)=5.32\cdot 10^4 g

6 0
2 years ago
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