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Alborosie
2 years ago
12

What volume is equivalent to 0.0015 m3?

Chemistry
1 answer:
Natali [406]2 years ago
8 0

1.5 x 10⁶mm³

Explanation:

 Here we are to convert m³ to mm³ or cm³ to see the correct option.

100cm = 1 m

1000mm = 1m

Converting to cm³ from m³;

  0.0015m³ = 1.5 x 10⁻³m³

Now:

    1.5 x 10⁻³  x m x m x m x \frac{100cm}{1m} x  \frac{100cm}{1m} x \frac{100cm}{1m}

    = 1.5 x 10³cm³

Also;

1.5 x 10⁻³  x m x m x m x \frac{1000mm}{1m} x  \frac{1000mm}{1m} x \frac{1000mm}{1m}

  =   1.5 x 10⁶mm³

learn more:

Volume brainly.com/question/2690299

#learnwithBrainly

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Solid aluminum metal and diatomic chlorine gas react spontaneously to form a solid product. Give the balanced chemical equation
ValentinkaMS [17]

When solid aluminum metal is reacted with diatomic chlorine gas, solid aluminum chloride is formed. This reaction is an example of synthesis or chemical combination in which two elements, aluminum and chlorine combine to form a new compound aluminum chloride.

Word equation: Aluminum (s)+ Chlorine (g)---> Aluminum chloride(s)

Molecular formula of the product formed is AlCl_{3}.

Therefore the balanced chemical equation representing the reaction of solid aluminum with gaseous dichlorine can be represented as,

2Al(s) + 3Cl_{2}(g)-->2AlCl_{3}(s)

8 0
2 years ago
To burn 1 molecule of C5H12 to form CO2 and H2O (complete combustion), how many molecules of O2 are required?
viva [34]
C5H12 + 8 O2 → 5 CO2 + 6 H2O 

8 molecules of O2 are required.
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2 years ago
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Identify the precipitate (if any) that forms when nach3coo (also written as nac2h3o2) and hcl are mixed. express your answer as
Karolina [17]
When NaCH3Coo mixed with HCl we will get NaCl and CH3CooH as shown in the following balanced equation:

NaCH3Coo + HCl → NaCl + CH3CooH
so from this equation, we can conclude that is no precipitate because all we get is the acetic acid which found in vinegar and the NaCl which is very soluble so we don't have any precipitate.
so, your answer is no precipitate, no reaction
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1 year ago
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Help on part "c": The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0g of luminol
Contact [7]

1. The molarity of the stock solution of luminol = 1,431 M

2. 0.12 moles of luminol is present in 2.00 L of the diluted spray

3. The volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B): 83.86 ml

<h3>Further explanation</h3>

Stoichiometry in Chemistry studies about chemical reactions mainly emphasizing quantitative, such as the calculation of volume, mass, amount, which is related to the number of ions, molecules, elements, etc.

In stoichiometry included :

  • 1. Relative atomic mass
  • 2. Relative molecular mass

is the relative atomic mass of the molecule

  • 3. mole

1 mole is the number of particles contained in a substance with the same number of atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) by the relative mass of the element or the relative mass of the molecule

\large{\boxed{\bold{mol\:=\:\frac{grams}{ relative\:mass} }}}

Luminol (C₈H₇N₃O₂) is a substance used to detect traces of blood in the scene of a crime because it reacts with iron in the blood

a. a luminol stock solution by adding 19.0g of luminol into a total volume of 75.0mL of H2O.

So the molarity is

  • 1. Luminol mole

- the relative molecular mass of Luminol

= 8. C + 7.H + 3.N + 2.16

= 8.12 + 7.1 + 3.14 + 2.16

= 177 grams / mol

so the mole:

mol = gram / relative molecular mass

mole=\frac{19}{177}

mole = 0.1073

2. Molarity (M)

M = mole / volume

M\:=\:{\frac{ 0.1703 }{75.10^{-3} L}

M = 1,431

  • b. luminol concentration in a spray bottle 6.00 × 10⁻² M. So that in 2 L of solution, the number of moles is:

mole = M x volume

mole = 6.10⁻² x 2

mole = 0.12

  • c. Molarity of the stock solution (Part A) = 1,431 M

the number of moles present in the diluted solution (Part B) = 0.12

So the volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B) is:

volume = mol / M

volume\:=\:\frac{0.12}{1.431}

volume = 0.08386 L = 83.86 ml

<h3>Learn more</h3>

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Keywords: mole, volume, molarity, Luminol, the relative molecular mass

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What is the amount of Al2S3 remains when 20.00 g of Al2S3 and 2.00 g of H2O are reacted? A few of the molar masses are as follow
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The remaining amount:
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= 0.1145 mol
Or
0.1145 * 150.17
= 17.19 grams
6 0
2 years ago
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