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Musya8 [376]
2 years ago
12

The ΔG for a particular enzyme-catalyzed reaction is -20 kcal/mol. If the amount of enzyme in the reaction is doubled, what will

be the ΔG for the new reaction?
Chemistry
1 answer:
LUCKY_DIMON [66]2 years ago
3 0

Answer:

The value of the of ΔG for the new reaction will be same as the given value of -20kcal/mol.

Explanation:

In an enzyme-catalyzed reaction, the concentration or amount of enzyme will not affect the equilibrium constant of the reaction due to which ΔG for the reaction will remain unaffected. Here enzymes are acting as a catalyst that cannot alter law thermodynamics and equilibrium of the reaction.

\Delta G=\Delta G^o+RT\ln K_{eq}

Since the enzyme amount will not affect the equilibrium of the reaction, the value of ΔG will remain the same as given -20 kcal/mol.

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space capsules operate with an oxygen content of about 34%. assuming a total pressure of 780 mm Hg in the space capsule, what is
Lemur [1.5K]

265.2 mmHg is the partial pressure of oxygen in 780 mmHg of total pressure.

Explanation:

The partial pressure of a gas is defined as the individual pressure of the gas in total mixture. In an ideal gas all the constituent gases have partial pressure some of which will give total pressure of the gas.

The partial pressure of a gas is calculated by

total pressure x mole fraction of the gas.

Mole fraction of the oxygen present is 0.34 as it is 34% of the total gas.

\frac{34}{100} = 0.34  is the mole fraction

Total pressure is given as 780 mm Hg

The partial pressure can be calculated using the above formula:

Putting the values in equation:

780 x 0.34

= 265.2 mm Hg is the partial pressure of oxygen.

7 0
2 years ago
Dry ice is solid carbon dioxide. A 0.050-g sample of dry ice is placed in an evacuated 4.6-L vessel at 30 °C. Calculate the pres
goldenfox [79]

The answer is 6.1*10^-3 atm.

The pictures and explanations are there.

3 0
2 years ago
A 0.500-mole sample of a gas has a volume of 11.2 liters at 273 k. what is the pressure of the gas? (hint: use ideal gas law equ
Ray Of Light [21]
Pv =nRT

T= 273
n = 0.500
v= 11.2 
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p= 0.5×0.08206×273 ÷ (11.2) =10.00
5 0
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Murrr4er [49]

Answer:

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