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Alja [10]
2 years ago
7

Determine the values of m and n when the following mass of the Earth is written in scientific notation: 5,970,000,000,000,000,00

0,000,000 kg. Enter m and n, separated by commas.
Physics
1 answer:
uysha [10]2 years ago
7 0

Answer: 5.97, 24

m = 5.97

n = 24

SN = 5.97 × 10^24 kg

Explanation:

Scientific notation or standard form is a way of rewriting very large or very small (minute) numbers in conveniently in decimal form. The standard way of writing scientific notation is of the form;

m × 10^n

To derive m, we need to reduce it to a number between 1 and 10 ( 10 exclusive)

For the case above ;

m = 5.97

To get the value of n, we need to count the number of digits from the right egde of the data to the point where we put the decimal.

For the case above;

n = 24

Therefore, the scientific notation of the mass of the earth is ;

M = 5.97 × 10^24 kg

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Bricks and insulation are used to construct the walls of a house. The
ira [324]

Answer:

\dot Q=350.438\ W

Explanation:

Given:

<u>the thermal resistance in the form of </u>

R_1=\frac{x_1}{k_1} =0.095\ m^2.^{\circ}C.W^{-1}

R_2=\frac{x_2}{k_2} =0.704\ m^2.^{\circ}C.W^{-1}

where:

x_1\  \&\ x_2 are the thickness of the respective bricks

k_1\ \&\ k_2 are the respective coefficient of conductivity

temperature inside the house, T_h=24\ ^{\circ}C

temperature outside the house, \ T_c=10^{\circ}C

area of the wall, A=20\ m^2

Since the bricks and insulation are used to construct a wall then they must be used in series for better shielding.

<u>Using Fourier's law:</u>

\dot Q=k.A.\frac{dT}{x}

\dot Q={dT}\div {\frac{x}{k.A} }

in series the resistances get add up

\dot Q=dT\div (\frac{x_1}{k_1.A}+\frac{x_2}{k_2.A} )

\dot Q=(24-10)\div (\frac{0.095 }{20}+ \frac{0.704 }{20} )

\dot Q=350.438\ W

7 0
2 years ago
In a circus act, an acrobat rebounds upward from the surface of a trampoline at the exact moment that another acrobat, perched 9
slega [8]

Answer:

1.6 secs

Explanation:

In a circus act, an acrobat upwards from the surface of a trampoline

At that same moment another acrobat perched 9.0m above him

A ball is released from rest

While still in motion the acrobat catches the ball

He left the ball with a trampoline of 5.6m/s

Since the ball is falling downwards from a distance then acceleration will be negative

a= -9.8

s= d

s= 1/2at^2

= 1/2 × (-9.8)t^2

= 0.5× (-9.8)t^2

d = -4.9t^2

Therefore the time the acrobat stays in the air before catching the ball can be calculated as follows

9 - 4.9t^2= 5.6t + 1/2(-9.8)t^2

9 - 4.9t^2= 5.6t + (-4.9)t^2

9 - 4.9t^2= 5.6t - 4.9t^2

9= 5.6t

t= 9/5.6

t= 1.6 secs

6 0
2 years ago
Water, of density 1000 kg/m3, is flowing in a drainage channel of rectangular cross-section. The width of the channel is 15 m, t
Rom4ik [11]

Answer:

Water flowing rate=  (300000kg/s) = (300000l/s)

Explanation:

First with the section of the channel, the depth of the water and the speed of the fluid we can determine the volume of fluid that circulates per second through the channel:

Volume per time= 15m × 8m × (2.5m/s)= 300 m³/s

With this volume of circulating fluid per second elapsed, we multiply it by the density of the water to determine the kilograms or liters of water that circulate through the channel per second elapsed:

Water flowing rate= (300m³/s) × (1000kg/m³)= (300000kg/s) = (300000l/s)

Taking into account that 1kg of water is approximately equal to 1 liter of water.

8 0
2 years ago
(8%) Problem 9: Helium is a very important element for both industrial and research applications. In its gas form it can be used
exis [7]

Answer:

2046.37 kPa

Explanation:

Given:

Number of moles, n = 125

Temperature, T = 20° C = 20 + 273 = 293 K

Radius of the cylinder, r = 17 cm = 0.17 m

Height of the cylinder, h = 1.64 m

thus,

volume of the cylinder, V = πr²h

= π × 0.17² × 1.64

= 0.148 m³

Now,

From the ideal gas law

we have

PV = nRT

here,

P is the pressure

R is the ideal gas constant = 8.314  J / mol. K

thus,

P × 0.148 = 125 × 8.314 × 293

or

P × 0.148 = 304500.25

or

P = 2046372.64 Pa = 2046.37 kPa

6 0
2 years ago
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natali 33 [55]

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6 0
2 years ago
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