A container of water is lifted vertically 3.0 m then returned to its original position. If the total weight is 30 N, how much wo
1 answer:
Answer:
Work done, W = 0 J
Explanation:
Given that,
The total weight of the container, W = 30 N
A container of water is lifted vertically 3 m then returned to its original position. We know that the difference in final and initial position of an object is called its displacement. Here, its displacement is equal to 0 as it reaches to its original position.
Work done is given by :
As d = 0
W = 0
So, no work was done by the container of water. Hence, this is the required solution.
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Answer:
(a). The initial velocity is 28.58m/s
(b). The speed when touching the ground is 33.3m/s.
Explanation:
The equations governing the position of the projectile are
where is the initial velocity.
(a).
When the projectile hits the 50m mark, ; therefore,
solving for we get:
Thus, the projectile must hit the 50m mark in 1.75s, and this condition demands from equation (1) that
which gives
(b).
The horizontal velocity remains unchanged just before the projectile touches the ground because gravity acts only along the vertical direction; therefore,
the vertical component of the velocity is
which gives a speed of