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2 years ago

A giant bat has an average mass of 250g. suppose a bat with this mass flies at 2.0m/s when it detects a giant bug

Physics

1 answer:

Anvisha [2.4K]2 years ago

8 0

Question

Determine its kinetic energy

Answer:

0.5 J

Explanation:

Kinetic energy is given by

$KE=0.5mv^{2}$ where m is the mass and v is the speed

Substituting 250g= 0.25 Kg for mass and 2 m/s for v then

$KE=0.5\times 0.25\times 2^{2}$ =0.5 J

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An astronaut stands on the surface of an asteroid. The astronaut then jumps such that the astronaut is no longer in contact with

Anna71 [15]

(D) The gravitational force between the astronaut and the asteroid.

Reason :

All the other forces given in the options, except (D), doesn't account for the motion of the astronaut. They are the forces that act between nucleons or atoms and neither of them accounts for an objects motion.

6 0

2 years ago

A square loop of wire has a perimeter of 4.00 mm and is oriented such that two of its parallel sides form a 13.0 ∘∘ angle with t

vivado [14]

Answer:

a) (2.436 × 10⁻⁷) Wb

b) (7.308 × 10⁻⁷) Wb

Explanation:

Magnetic flux is the dot product of the magnetic field vector and the Area vector.

Mathematically, it is given as

Φ = BA cos θ

where B = magnetic field strength

A = Cross sectional Area of the loop enclosed

θ = angle between the magnetic field and the plane of the area.

a) B = 0.250 T

To find A, the perimeter of the loop is given as 4.00 mm.

Perimeter of a square = 4L

4L = 4.00

L = 1.00 mm = 0.001 m

The area is given as L²

A = (0.001)² = 0.000001 m²

θ = 13°

Φ = BA cos θ

Φ = 0.25 × 0.000001 × cos 13°

Φ = 0.0000002436 Wb = (2.436 × 10⁻⁷) Wb

b) Another loop lies in the same plane but has an irregular shape, resembling a starfish. Its area is three times greater than that of the square loop

Φ = BA cos θ

B = 0.25 T

A = 3 × 0.000001 = 0.000003 m²

θ = 13°

Φ = 0.25 × 0.000003 × cos 13°

Φ = 0.0000007308 Wb = (7.308 × 10⁻⁷) Wb

Hope this Helps!!!

8 0

2 years ago

A box of mass 8 kg slides across a frictionless surface at an initial speed 1.5 m/s into a relaxed spring of spring constant 69

Sav [38]

Answer:

1.1 sec

Explanation:

m = mass of the box = 8 kg

k = spring constant of the spring = 69 N/m

v = initial speed of the box = 1.5 m/s

t = time period of oscillation of box in contact with the spring

Time period is given as

$t = \pi \sqrt{\frac{m}{k}}$

Inserting the values

$t = (3.14) \sqrt{\frac{8}{69}}$

t = 1.1 sec

5 0

2 years ago

The difference between the two molar specific heats of a gas is 8000J/kgK. If the ratio of the two specific heats is 1.65, calcu

Serjik [45]

Answer:

sorry

Explanation:

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2 years ago

A pair of glasses is dropped from the top of a 32.0m stadium. A pen is dropped 2.Os later. How high above the ground is the pen

Svetllana [295]

Answer:

$h_p = 30.46\ m$

Explanation:

<u>Free Fall Motion</u>

A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.

The speed vf of the object when a time t has passed is given by:

$v_f=g\cdot t$