A gas occupies 0.60 m3 at a 5.0 atm. If the temperature of the gas remains the same and the pressure decreases to 2.5 atm, what

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2 years ago

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would be the new volume occupied by the gas?
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Answer:

1 answer:

kykrilka [37] · Answer 1 · 2023-06-17T20:46:06+03:00

The new volume of the gas is $1.20 m^3$

Explanation:

For a gas kept at constant temperature, we can apply Boyle's law, which states that:

"For a gas kept at constant temperature, the product of the gas pressure and of its volume remains constant"

Mathematically:

$pV=const.$

where

p is the gas pressure

V is its volume

For this problem, we can rewrite the equation as

$p_1 V_1 = p_2 V_2$

where:

$p_1 = 5.0 atm$ is the initial pressure of the gas

$V_1 = 0.60 m^3$ is the initial volume of the gas

$p_2 = 2.5 atm$ is the final pressure of the gas

$V_2$ is the final volume of the gas

And solving for $V_2$ , we find:

$V_2=\frac{p_1 V_1}{p_2}=\frac{(5.0)(0.60)}{2.5}=1.20 m^3$

Learn more about ideal gases:

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