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2 years ago

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Which model is used to describe the interaction of external forces that affect an organization's strategy and ability to compete

?

1 answer:

Diano4ka-milaya [45]2 years ago

5 0

Answer:

Competitive forces model

Explanation:

A Competitive forces model is the important tool which is used in the strategic analysis to determine the competitiveness in an organization. The model is commonly known as the "Five Force Model of Porter", which includes five forces — intensity of a rivalry, the bargaining ability of the buyers, threat of the potential new entrants, the bargaining power of a supplier, and the threat of substitute goods or services.

It affects the organizations's ability to compete as well as the strategy to succeed.

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A biophysics experiment uses a very sensitive magnetic field probe to determine the current associated with a nerve impulse trav

fenix001 [56]

Answer:

The peak current carried by the axon is 5.85 x 10⁻⁸ A

Explanation:

Given;

distance of the field from the axon, r = 1.3 mm

peak magnetic field strength, B = 9 x 10⁻¹² T

To determine the peak current carried by the axon, apply the following equation;

$B = \frac{\mu I}{2\pi r}$

where;

B is the peak magnetic field

r is the distance of the magnetic field from axon

μ is permeability of free space = 4π x 10⁻⁷

I is the peak current

Re-arrange the equation and solve for "I"

$B = \frac{\mu I}{2\pi r} \\\\I = \frac{B*2\pi r}{\mu} \\\\I = \frac{9*10^{-12}*2*\pi *1.3*10^{-3}}{4\pi *10^{-7}} \\\\I = 5.85 *10^{-8} \ A$

Therefore, the peak current carried by the axon is 5.85 x 10⁻⁸ A

7 0

2 years ago

How much does a person weigh if it takes 700 kg*m/s to move them 10 m/s<br><br> NEED ASAP

madreJ [45]

Answer:

$\huge\boxed{m = 70 \ kg}$

Explanation:

<u>Given Data:</u>

Momentum = P = 700 kg m/s

Velocity = v = 10 m/s

<u>Required:</u>

Mass = m = ?

<u>Formula:</u>

P = mv

<u>Solution:</u>

m = P / v

m = 700 / 10

m = 70 kg

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AnonymousHelper1807</h3>

5 0

2 years ago

Ugonna stands at the top of an incline and pushes a 100−kg crate to get it started sliding down the incline. The crate slows to

Anna [14]

Answer:(a)891.64 N

(b)0.7

Explanation:

Mass of crate $m=100 kg$

Crate slows down in $s=1.5 m$

initial speed $u=1.77 m/s$

inclination $\theta =30^{\circ}$

From Work-Energy Principle

Work done by all the Forces is equal to change in Kinetic Energy

$W_{friction}+W_{gravity}=\frac{1}{2}mv_i^2-\frac{1}{2}mv_f^2$

$W_{gravity}=mg(0-h)=mgs\sin \theta$

$W_{gravity}=-mgs\sin \theta$

$W_{gravity}=-100\times 9.8\times 1.5\sin 30=-735 N$

change in kinetic energy $=\frac{1}{2}\times 100\times 1.77^2=156.64 J$

$W_{friction}=156.64+735=891.645$

(b)Coefficient of sliding friction

$f_r\cdot s=W_{friciton}$

$891.645=f_r\times 1.5$

$f_r=594.43 N$

and $f_r=\mu mg\cos \theta$

$\mu 100\times 9.8\times \cos 30=594.43$

$\mu =0.7$

5 0

2 years ago

A sound technician is testing the sound acoustics in a theatre for an upcoming music concert. He sets up speakers in different l

velikii [3]

Consertive alex dggghh

4 0

2 years ago

A motorcycle of mass 100 kilograms travels around a flat, circular track of radius 10 meters with a constant speed of 20 meters

JulijaS [17]

Answer:

100/10 = 10 , 10 × 10 = 100÷20 = 5

I'm pretty sure its wrong

8 0

2 years ago

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