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mina [271]
2 years ago
10

Observe the reactions given below. Classify the reactants based on whether they are oxidized or reduced. Zn(s)+Cu2+(aq)→Zn2+(aq)

+Cu(s) 3Fe(s)+4H2O(g)→Fe2O3(s)+4H2(g) Drag the appropriate items to their respective bins. View Available Hint(s)
Chemistry
1 answer:
Natalija [7]2 years ago
7 0

Answer:

1. Zn is oxidize.

Cu is reduced.

2. Fe is oxidize.

H2 is reduced.

Explanation:

1. Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)

From the equation,

Zn changes oxidation number from 0 to +2. Therefore Zn is oxidized.

Cu2+ changes oxidation number from +2 to 0. Therefore, Cu2+ is reduced

2. 3Fe(s)+4H2O(g)→Fe2O3(s)+4H2(g)

From the equation,

Fe changes oxidation number from 0 to +3. Therefore, Fe is oxidized.

H changes oxidation number from +1 to 0. Therefore, H is reduced

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The pKs of succinic acid are 4.21 and 5.64. How many grams of monosodium succinate (FW = 140 g/mol) and disodium succinate (FW =
Varvara68 [4.7K]

Answer:

9.744g of monosodium succinate.

4.925g of disodium succinate.

Explanation:

To find pH of the buffer produced by the mixture of monosodium succinate-Disodium succinate is obtained from H-H equation:

pH = pKa + log ([Na₂Suc] / [NaHSuc])

As you want a pH of 5.28 and pKa is 5.64:

5.28 = 5.64 + log ([Na₂Suc] / [NaHSuc])

-0.36 = log ([Na₂Suc] / [NaHSuc])

0.4365 = ([Na₂Suc] / [NaHSuc]) <em>(1)</em>

<em />

As total concentration of the buffer is 100mM = 0.100M:

0.100M = [Na₂Suc] + [NaHSuc] <em>(2)</em>

Replacing (2) in (1):

0.4365 = (0.100M - [NaHSuc] / [NaHSuc])

0.4365 = (0.100M - [NaHSuc] / [NaHSuc])

0.4365 [NaHSuc] = 0.100M - [NaHSuc]

1.4365 [NaHSuc] = 0.100M

[NaHSuc] = 0.0696M

And:

[Na₂Suc] = 0.0304M

As volume of the buffer is 1L:

[NaHSuc] = 0.0696 moles

[Na₂Suc] = 0.0304 moles

Using molar mass of both substances:

Mass of monosodium succinate:

0.0696moles * (140g / 1mol) =<em> 9.744g of monosodium succinate.</em>

Mass of disodium succinate:

0.0304moles * (162g / 1mol) =<em> 4.925g of disodium succinate.</em>

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5 0
2 years ago
For no2−, write an equation that shows how the anion acts as a base. express your answer as a chemical equation. identify all of
katrin [286]
Hello!

Bases are defined by Arrhenius as substances which release OH⁻ ions when dissolved in water. NO₂⁻ complies with this definition by the chemical reaction that is shown below:

 NO₂⁻(aq) + H₂O (l) HNO₂ (aq) + OH⁻(aq)

Have a nice day!
5 0
2 years ago
Read 2 more answers
Consider the structure of the amino acid alanine. indicate the hybridization about each interior atom.
OLEGan [10]
The structure of Alanine is shown below,
Except the carbon atom of carbonyl group which is Sp² Hybridized, all remaining atoms are Sp³ Hybridized. The hybridization of each element is depicted in a box below,

5 0
2 years ago
Read 2 more answers
Which of the following shows a Bronsted-Lowry acid reacting?
7nadin3 [17]
<h3>Answer:</h3>

         Option-C:  HCl + H₂O  →   H₃O⁺ + Cl⁻

Explanation:

       Bronsted-Lowery concept of Acid and Base defines Acid as that specie which tends to donate H⁺ (Hydrogen Ion) and bases are those species which accepts H⁺ from Acids.

In selected option, HCl is reacting as Acid as it donates H⁺ to water (lowery bronsted base).

Also, the correspong acid is converted into conjugate base (i.e. Cl⁻) and base is converted into conjugate acid (i.e. H₃O⁺)

8 0
2 years ago
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Groups of atoms that are added to carbon backbones and give them unique properties are known as
Irina-Kira [14]

Answer:

             Groups of atoms that are added to carbon backbones and give them unique properties are known as <u>Functional Groups</u>.

Explanation:

                   In organic chemistry they are called as Functional Group because they are the active part of a molecule. These groups give a unique characteristic to molecule both chemically and physically. Also, each functional group represent a different class of compounds.

Examples:

S No.                          Functional Group                                 Name

1                                   R--X                                             Alkyl Halides

2                                   R--OH                                          Alcohols

3                                  R--NH₂                                         Amines

4                                  R--O--R                                         Ethers

5                                   R--CO--R                                      Ketones

6                                   R--CO--H                                     Aldehydes

7                                  R--CO--OH                                  Carboxylic acids

8                                   R--CO--X                                     Acid Halides

10                                R--CO--NR₂                                 Acid Amides

11                                 R--CO-OR'                                  Esters

3 0
2 years ago
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