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balandron [24]
2 years ago
12

In a water park, there is a wave pool with large paddles that create waves from the left, right, and center walls that surround

it. In one small center section of the wave pool, the waves are much smaller than the surrounding waves. What wave phenomenon best explains why these waves are smaller compared to the rest of waves in the pool? Reflection off the pool walls Diffraction between paddles Constructive interference Destructive interference
Physics
1 answer:
Goryan [66]2 years ago
3 0

Answer:

Destructive interference

Explanation:

Wave pools are artificially-designed swimming pools which generate waves just like in the ocean. They have been designed in order to imitate the movement of ocean waves. So, in order to do this, waves have to be created either by "pressurized air" or "paddles."

The surrounding waves tend to be bigger than the smaller section of the wave pool because of "destructive interference." This happens when the<em> crest</em> <em>(the point with a maximum value of upward displacement)</em> of one wave meets the <em>trough</em> <em>(the lowest point in the cycle)</em> of another wave. The result is a "lower total amplitude." The amplitude here refers to the difference of individual amplitudes.

So, this explains why the waves are much smaller in one small center section than the surrounding waves.

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Explanation:

a)

The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).

The graph of the problem is missing, find it in attachment.

To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.

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b)

The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.

The perimeter of the wheel is:

L=2\pi R

where R is the radius of the wheel.

The period of revolution is:

T=120 s

Therefore, the tangential speed of the book is:

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Answer:

S_i=\frac{9}{10} =0.9

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Given:

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  • the volume level of oil when the ice melted, V'=87\ cm^3

<u>Now, therefore the volume of ice:</u>

V_i=V-V_o

V_i=90-60

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<u>Now the volume of water:</u>

V_w=V'-V_o

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As we know that the relative density is the ratio of density of the substance to the density of water.

<u>So, the relative density of ice:</u>

S_i=\frac{\rho_i}{\rho_w} .....................(1)

as we know that density is given as:

\rm \rho=\frac{mass}{volume}

now eq. (1)

S_i=\frac{m}{V_{i}}\div  \frac{m}{V_w}

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S_i=\frac{9}{10} =0.9

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