Light with a wavelength of 600 nm is incident on a diffraction grating that has 100 slits. The first-order maximum is observed a
t a point P on a distant screen. How much farther does the light travel from the first slit of the grating to point P than does the light from the 100th slit?
1 answer:
Answer:
How much farther does the light travel from the first slit of the grating to point P = 59.4miu-m
Explanation:
The concept of constructive interference is applied here, the constructive interference condition is used to find the expression for the path difference. once the expression has been extablished, the wavelength can now be substituted to get the path difference as the step by step calculation is shown in the attached file.
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Answer:
9.6x10¹³watt
Explanation:
See attached file
Answer:
The equation of displacement is .
Explanation:
Given that,
Distance = 2.50 m
We need to calculate the equation of wave
Using general equation of wave
....(I)
Where, A = amplitude
t = time
x = displacement
= phase difference
Put the value in the equation
At t = 0, x = 0, y =A
From equation (I)
Hence, The equation of displacement is .