P=25x10^6 andF=750.So plug in everything to solve for A. which is 3x10^-5m^2 OR 0.3mm^2
Which statements describe how chemical formulas, such as H2O, represent compounds? Check all that apply.
2 answers:
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P=25x10^6 andF=750.So plug in everything to solve for A. which is 3x10^-5m^2 OR 0.3mm^2
Answer:
130.5
Explanation:
According to the stemplot attached (Which I think it is, and if not, then you only need to replace the procedure with your data and you should be fine), you need to calculate first the points of all ten students. In that plot, we can easily calculate the points.
The first number in the colum represents the centen of the point, while the numbers of the second column, represents the units of that centen, for example if you see:
16 | 8 5 6
This means that the point for the students are 168, 165 and 166. Three students, three points.
If you watch the stemplot, the points for the students are:
116, 118, 121, 124, 128, 133, 137, 142, 146 and 179.
The median can be calculated using the mean between the two values in the middle of the sequence.
In this case, half of ten is 5, so, the numbers from the middle in this sequence are 128 and 133, therefore:
Median = 128 + 133 / 2 = 130.5
Answer:
(a) 2.8 V
(b) 5.6 V
(c) 9.8 V
Explanation:
Given:
Frequency of the generator (f) = 1300 Hz)
Terminal voltage (V) =12.0 V
Resistance of resistor (R) = 14.0 Ω
Capacitance of capacitor (C) = 4.40 μF = 4.40 × 10⁻⁶ F
Inductance of the inductor (L) = 6.00 mH = 6.00 × 10⁻³ H
In order to find the voltages across each, we first need to find the reactance and impedance.
Reactance of the inductor is given as:
Reactance of the capacitor is given as:
Now, impedance is given as:
Current across the circuit is given as:
As resistor, capacitor and inductor are connected in series, the current across each of them is same and equal to total current in the circuit.
(a)
Voltage across the resistor is given as:
Therefore, the voltage across resistor is 2.8 V.
(b)
Voltage across the capacitor is given as:
Therefore, the voltage across the capacitor is 5.6 V.
(c)
Voltage across the inductor is given as:
Therefore, the voltage across the inductor is 9.8 V.