Transverse wave as the wave is going up and down no compressions
<span>Answer:
KE = (11/2)mω²r²,
particle B must have mass of 2m, while A has mass m.
Then the moment of inertia of the system is
I = Σ md² = m*(3r)² + 2m*r² = 11mr²
and then
KE = ½Iω² = ½ * 11mr² * ω² = 11mr²ω² / 2
So I'll proceed under that assumption.
For particle A, translational KEa = ½mv²
but v = ω*d = ω*3r, so KEa = ½m(3ωr)² = (9/2)mω²r²
For particld B, translational KEb = ½(2m)v²
but v = ω*r, so KEb = ½(2m)ω²r²
so total translational KE = (9/2 + 2/2)mω²r² = 11mω²r² / 2
which is equal to our rotational KE.</span>
Answer:
ma= ma
m⋅a = m⋅a
And equivalently:
am=ma
a⋅m = m⋅a
Explanation:
Question
Assuming this question "Similar to what you see in your textbook, you can generally omit the multiplication symbol as you answer questions online, except when the symbol is needed to make your meaning clear. For example, 1*10^5 is not the same as 110^5 . When you need to be explicit, type * (Shift + 8) to insert the multiplication operator. You will see a multiplication dot (⋅) appear in the answer box. Do not use the symbol x. For example, for the expression ma,
typing m⋅a would be correct, but mxa would be incorrect".
Solution to the problem
For this case we want to write a expression for ma, and based on the previous info we can write:
ma= ma
m⋅a = m⋅a
And equivalently:
am=ma
a⋅m = m⋅a
But is not correct do this:
mxa=mxa
axm = mxa
Answer:
Hello there use something that looks like this
Explanation:
This is an accurate representation of something you are working on!
As you can see the wire and the core are represented on the left and is showing how it can be represented on your right hand and how they are similar!
by making qualitative observations about the sodium hydroxide and phenolphthalein in solution
by comparing the given solution to other familiar solutions containing phenolphthalein
by designing an experiment to test phenolphthalein with other solutions
