Waves are observed to splash upon the rocks at the shore every 6.0
1 answer:
Explanation:
Given that,
Waves are observed to splash upon the rocks at the shore every 6.0 seconds
The distance measured from crest to adjacent crest is 8.0 m
The distance measured from the lowest to the highest point on the medium is 10.0 m.
We need to find the frequency, wavelength and speed of these waves. We know that the distance measured from crest to adjacent crest is called wavelength of a wave. So,
The inverse of time taken by the wave is called its frequency,
f = 0.167 Hz
The speed of a wave is the product of frequency and wavelength. It is given by :
v = 1.336 m/s
Hence, this is the required solution.
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Answer:
the direction that should be walked by Ricardo to go directly to Jane is 23.52 m, 24° east of south
Explanation:
given information:
Ricardo walks 27.0 m in a direction 60.0 ∘ west of north, thus
A= 27
Ax = 27 sin 60 = - 23.4
Ay = 27 cos 60 = 13.5
Jane walks 16.0 m in a direction 30.0 ∘ south of west, so
B = 16
Bx = 16 cos 30 = -13.9
By = 16 sin 30 = -8
the direction that should be walked by Ricardo to go directly to Jane
R = √A²+B² - (2ABcos60)
= √27²+16² - (2(27)(16)(cos 60))
= 23.52 m
now we can use the sines law to find the angle
tan θ =
= By - Ay/Bx -Ax
= (-8 - 13.5)/(-13.9 - (-23.4))
θ = 90 - (-8 - 13.5)/(-13.9 - (-23.4))
= 24° east of south
Answer:
Explanation:
Considering the thermal conductivity of aluminium and brass as and
respectively
The temperature at the end of aluminium and brass are given as and
respectively with length of rod L=1.3 m , Length of aluminium
, length of brass
and letting temperature at steady state be T
At steady state, thermal conductivity of both aluminium and brass are same hence
Upon re-arranging
Therefore, the temperatures at which the metals are joined is
a) Average power: 1425 W
b) Instantaneous power at 3.0 sec: 2850 W
Explanation:
a)
The motion of the object along the ramp is a uniformly accelerated motion (because the force applied is constant), so we can use the suvat equation
where
s = 18 m is the displacement along the ramp
u = 0 is the initial velocity
t = 3.0 s is the time taken
a is the acceleration of the object along the ramp
Solving for a,
Now we can apply Newton's second law to find the net force on the object:
This net force is the resultant of the applied force forward () and the component of the weight acting backward (
), so we can find what is the applied force:
where
m = 24 kg is the mass of the object
is the acceleration of gravity
Now we can finally find what is the work done by the applied force, which is parallel to the ramp, therefore:
where s = 18 m is the displacement.
Therefore the average power needed is:
b)
The instantaneous power at any point of the motion is given by
where
is the force applied
v is the velocity of the object
We already calculated the applied force:
While since this is a uniformly accelerated motion, we can find the velocity at the end of the 3.0 seconds using the suvat equation:
And therefore, the instantaeous power at 3.0 sec is:
Learn more about power:
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